← Senior Mathematics Studio

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A student squares the equation and obtains four candidates. Identify which must be rejected and why.

Read the idea, work independently, then explain what changed.

TOPIC 01

Complete trigonometric solution sets

Solve a transformed angle, recover every branch and intersect the original interval.

What you will be able to explain

  • Retain all angle branches and periodic copies in the requested interval.
  • Detect lost solutions from division and extraneous solutions from squaring.

Try it. Leave your reasoning visible.

Use one hint at a time. A correction explains what changed, not just the final answer.

Examples 1–3: study a full demonstration; finish a solution from its first step; then choose a method independently before opening the solution. The remaining exercises may continue after class.

01 / Standard#Your turn

A student squares the equation and obtains four candidates. Identify which must be rejected and why.

sin⁡x=−1/2,0≤x<360∘\sin x=-1/2,\quad0\le x<360^\circ
  • Degrees; original right-hand side negative.
Skills and prerequisite lessons

Scope: JM01 / JM02

Working and explanation

BUILD THE REASONING

Hint 1
Squaring erases the required negative sign.
Hint 2
Test the upper-half-circle candidates in the original equation.
Worked solution
  1. The squared equation allows both signs.

    x=30∘,150∘,210∘,330∘x=30^\circ,150^\circ,210^\circ,330^\circ
  2. Reject the positive-sine candidates.

    x=210∘,330∘ remainx=210^\circ,330^\circ\text{ remain}

Reject 30° and 150°; retain 210° and 330°.

Checks and common pitfalls: Substitution checks validity after an implication that was not reversible.

Reasoning checklist · self / teacher assessment
  • The squared equation allows both signs.
  • Reject the positive-sine candidates.

Think first. Reveal a hint when the class is ready.

Focus on one question

Teacher preparation and assessment

40-minute lesson

MinutesFocusTeaching and student action
5Branch diagnosisUse diagnostics to distinguish principal values and transformed intervals.
8Build solution setsMark equal-height points and periodic copies before filtering.
10Audit operationsPairs contrast safe division in sin x=cos x with lost roots in sin 2x=cos x.
12Classify and modelGroups classify parameter root counts and translate the wheel threshold.
5Exit completenessRequire a complete set and a reason no other branch fits.

Question sequence

  • What interval does the transformed angle actually traverse?
  • Did this operation lose or add candidates?

Board development

  • Preserve factor branches.
    cos⁡x(2sin⁡x−1)=0\cos x(2\sin x-1)=0
  • Map an angle interval back to time.
    π/6<πt/4<5π/6\pi/6<\pi t/4<5\pi/6

Expected correct and incorrect responses

  • “Both endpoints count because they are different real x-values” correctly handles k=0.
  • “Divide by cosine immediately” risks losing valid zero-factor solutions.

Follow-up questions

  • Why does substituting all found roots not prove that none were missed?

Remediation

  • For missing branches, draw the horizontal value line before invoking inverse trigonometry.
  • For transformed-interval errors, put x bounds and angle bounds in separate columns.

Exit check

  • Solve cos 2x=1 for 0≤x≤2π. Expected 0,π,2π with closed endpoints.

Assessment checklist and sample responses

  • 2 marks: branch and domain completeness.
    Full: four roots for sin 2x=1/2 on [0°,360°); partial: first two only.
  • 2 marks: validate nonreversible steps.
    Full: reject positive-sine roots after squaring; partial: accept all four squared-equation roots.

No sign-in. Work stays in this browser. Export before clearing browser data. Written reasoning is assessed with a checklist.

Curriculum and source notes ↗