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Unit-circle coordinates and signs

Read the idea, work independently, then explain what changed.

高一必修 第一册(A版).pdf · 5.2 · PDF 184 / printed page 177

TOPIC 01

Unit-circle coordinates and signs

Read sine and cosine as coordinates, retaining angle direction and quadrant information.

What you will be able to explain

  • Normalise a point to the unit circle and explain coordinate signs.
  • Use a norm check to judge whether proposed sine/cosine data are possible.

Coordinates before ratios

Coordinate signs survive normalisation; length alone does not determine a quadrant.

For a nonzero terminal-ray point, divide both coordinates by its positive radius.

cos⁡θ=x/r,sin⁡θ=y/r,r=x2+y2\cos\theta=x/r,\quad\sin\theta=y/r,\quad r=\sqrt{x^2+y^2}
  1. Scale the point by its radius.

    (x,y)↦(x/r,y/r)(x,y)\mapsto(x/r,y/r)
  2. Pythagoras becomes a unit-circle constraint.

    cos⁡2θ+sin⁡2θ=1\cos^2\theta+\sin^2\theta=1

When it applies

  • r>0; the origin has no terminal direction.

Counterexample: P=(−3,4) has negative cosine even though every side length is positive.

  • Link an oriented ray, signed coordinates and a unit-circle point.

Direction and admissible ratios

A rotation model needs orientation and units before a trig value is chosen.

Counterclockwise angles are positive; tangent is undefined when the x-coordinate is zero.

tan⁡θ=sin⁡θ/cos⁡θ\tan\theta=\sin\theta/\cos\theta
  1. Add complete turns without changing the terminal point.

    θ∼θ+360∘k\theta\sim\theta+360^\circ k
  2. Inspect the divisor before using tangent.

    cos⁡θ≠0\cos\theta\ne0

When it applies

  • Degree and radian measures must not be mixed; tangent requires nonzero cosine.

Counterexample: tan 90° is undefined, not zero.

  • Compare degree/radian labels and clockwise/counterclockwise arrows.

PREDICT → EXPLORE → EXPLAIN → TRANSFER

Make a prediction, then explore the relationship.

Lesson question: Which coordinate changes when θ is reflected to −θ or π−θ?

Model exploration: predict which displayed result changes with the parameters, check the values, and compare the observation with the lesson question.

Physical point (-1,1.73205); divide by positive r=2 for the unit-circle coordinates. Positive angles turn counterclockwise.xy

Physical point (-1,1.73205); divide by positive r=2 for the unit-circle coordinates. Positive angles turn counterclockwise.

Numerical data for the diagram; printable
QuantityValue
θ (rad)2.0944
x-1
y1.73205
cos θ-0.5
sin θ0.86603
tan θ-1.73205

Explain: Track signed coordinates and the tangent denominator while varying radius and angle.

Transfer: Choose two different-radius points with identical trig ratios.

Try it. Leave your reasoning visible.

Use one hint at a time. A correction explains what changed, not just the final answer.

Examples 1–3: study a full demonstration; finish a solution from its first step; then choose a method independently before opening the solution. The remaining exercises may continue after class.

01 / Foundation#Worked example

The terminal ray passes through P. Find cosine.

P=(−3,4)P=(-3,4)
  • P is nonzero.
Skills and prerequisite lessons

Scope: JM01 / JM02

Working and explanation

BUILD THE REASONING

Hint 1
Find the positive radius.
Hint 2
Cosine uses the horizontal coordinate.
Worked solution
  1. Normalise by the distance from the origin.

    r=9+16=5r=\sqrt{9+16}=5
  2. Retain the sign of x.

    cos⁡θ=−3/5\cos\theta=-3/5

−3/5.

Checks and common pitfalls: Distance is positive, while the leftward coordinate is negative.

Think first. Reveal a hint when the class is ready.

02 / Standard#Worked example

Find cosine from the given sine and quadrant.

sin⁡θ=3/5,θ in quadrant II\sin\theta=3/5,\quad\theta\text{ in quadrant II}

First step provided — complete the reasoning:Find the squared cosine.

cos⁡2θ=1−9/25=16/25\cos^2\theta=1-9/25=16/25
  • Angle lies strictly in quadrant II.
Skills and prerequisite lessons

Scope: JM01 / JM02

Working and explanation

BUILD THE REASONING

Hint 1
Use the unit-circle identity.
Hint 2
Choose the negative square-root branch in quadrant II.
Worked solution
  1. Find the squared cosine.

    cos⁡2θ=1−9/25=16/25\cos^2\theta=1-9/25=16/25
  2. Apply the quadrant sign.

    cos⁡θ=−4/5\cos\theta=-4/5

−4/5.

Checks and common pitfalls: The identity alone gives two signs; the quadrant selects one.

Think first. Reveal a hint when the class is ready.

03 / Transfer#Worked example

A sensor reports a counterclockwise turn of 765° from the positive x-axis on a unit circle. Give its final coordinates and explain why reducing turns is valid.

θ=765∘\theta=765^\circ
  • Radius 1; positive rotation is counterclockwise.
Skills and prerequisite lessons

Scope: JM01 / JM02

Working and explanation

BUILD THE REASONING

Hint 1
Remove complete turns, not a half-turn.
Hint 2
765−720=45.
Worked solution
  1. Find the coterminal angle.

    765∘=2(360∘)+45∘765^\circ=2(360^\circ)+45^\circ
  2. Read the equal positive coordinates at 45°.

    P=(2/2,2/2)P=(\sqrt2/2,\sqrt2/2)

(√2/2,√2/2).

Checks and common pitfalls: Full turns preserve the endpoint, while the recorded travel still totals 765°.

Think first. Reveal a hint when the class is ready.

04 / Foundation#Your turn

Evaluate.

sin⁡150∘\sin150^\circ
  • Angles are in degrees.
Skills and prerequisite lessons

Scope: JM01 / JM02

Working and explanation

BUILD THE REASONING

Hint 1
The reference angle is 30°.
Hint 2
Sine is positive in quadrant II.
Worked solution
  1. Reflect a 30° point across the y-axis.

    150∘=180∘−30∘150^\circ=180^\circ-30^\circ
  2. The vertical coordinate is preserved.

    sin⁡150∘=1/2\sin150^\circ=1/2

1/2.

Checks and common pitfalls: Reflection changes cosine, not this sine.

Think first. Reveal a hint when the class is ready.

05 / Foundation#Your turn

Evaluate.

cos⁡240∘\cos240^\circ
  • Angles are in degrees.
Skills and prerequisite lessons

Scope: JM01 / JM02

Working and explanation

BUILD THE REASONING

Hint 1
240° is in quadrant III.
Hint 2
Its reference angle is 60°.
Worked solution
  1. Separate the half-turn.

    240∘=180∘+60∘240^\circ=180^\circ+60^\circ
  2. The horizontal coordinate reverses sign.

    cos⁡240∘=−1/2\cos240^\circ=-1/2

−1/2.

Checks and common pitfalls: A half-turn reverses both coordinates.

Think first. Reveal a hint when the class is ready.

06 / Foundation#Your turn

Explain the status of tan 90°.

tan⁡90∘\tan90^\circ
  • Real trigonometric functions are used.
Skills and prerequisite lessons

Scope: JM01 / JM02

Working and explanation

BUILD THE REASONING

Hint 1
Use sin/cos.
Hint 2
The denominator is zero.
Worked solution
  1. Read the point at a quarter-turn.

    (cos⁡90∘,sin⁡90∘)=(0,1)(\cos90^\circ,\sin90^\circ)=(0,1)
  2. The quotient cannot be a real number.

    1/0 undefined1/0\text{ undefined}

Undefined.

Checks and common pitfalls: It is neither zero nor a real infinite value.

Reasoning checklist · self / teacher assessment
  • Read the point at a quarter-turn.
  • The quotient cannot be a real number.

Think first. Reveal a hint when the class is ready.

07 / Foundation#Your turn

Give the unit-circle coordinates.

θ=−π/3\theta=-\pi/3
  • The input is in radians.
Skills and prerequisite lessons

Scope: JM01 / JM02

Working and explanation

BUILD THE REASONING

Hint 1
A negative angle rotates clockwise.
Hint 2
The magnitude is 60°.
Worked solution
  1. Locate quadrant IV.

    −π/3=−60∘-\pi/3=-60^\circ
  2. Cosine is positive and sine negative.

    P=(1/2,−3/2)P=(1/2,-\sqrt3/2)

(1/2,−√3/2).

Checks and common pitfalls: The radian input must be interpreted as an angle, not a degree number.

Reasoning checklist · self / teacher assessment
  • Locate quadrant IV.
  • Cosine is positive and sine negative.

Think first. Reveal a hint when the class is ready.

08 / Standard#Your turn

Find sine.

cos⁡θ=−12/13,θ in quadrant III\cos\theta=-12/13,\quad\theta\text{ in quadrant III}
  • Angle is in quadrant III.
Skills and prerequisite lessons

Scope: JM01 / JM02

Working and explanation

BUILD THE REASONING

Hint 1
Use squared coordinates summing to 1.
Hint 2
Sine is negative in quadrant III.
Worked solution
  1. Find the squared vertical coordinate.

    sin⁡2θ=1−144/169=25/169\sin^2\theta=1-144/169=25/169
  2. Select the negative branch.

    sin⁡θ=−5/13\sin\theta=-5/13

−5/13.

Checks and common pitfalls: The sign is supplied by the quadrant, not by the square root computation.

Think first. Reveal a hint when the class is ready.

09 / Standard#Your turn

Find cosine exactly.

tan⁡θ=−2,θ in quadrant IV\tan\theta=-2,\quad\theta\text{ in quadrant IV}
  • Cosine is nonzero; quadrant IV fixes its sign.
Skills and prerequisite lessons

Scope: JM01 / JM02

Working and explanation

BUILD THE REASONING

Hint 1
Use a ray with coordinate ratio −2.
Hint 2
Choose point (1,−2).
Worked solution
  1. Choose a representative point with the correct quadrant.

    P=(1,−2),r=5P=(1,-2),\quad r=\sqrt5
  2. Normalise the horizontal coordinate.

    cos⁡θ=1/5\cos\theta=1/\sqrt5

1/√5.

Checks and common pitfalls: A ratio does not fix length, but normalisation removes that freedom.

Reasoning checklist · self / teacher assessment
  • Choose a representative point with the correct quadrant.
  • Normalise the horizontal coordinate.

Think first. Reveal a hint when the class is ready.

10 / Standard#Your turn

Give the angle in degrees in [0,360).

P=(0,−2)P=(0,-2)
  • Answer in degrees, 0≤θ<360°.
Skills and prerequisite lessons

Scope: JM01 / JM02

Working and explanation

BUILD THE REASONING

Hint 1
Locate the negative y-axis.
Hint 2
Use the positive counterclockwise representative.
Worked solution
  1. The terminal direction is downward.

    (x/r,y/r)=(0,−1)(x/r,y/r)=(0,-1)
  2. Choose the requested interval representative.

    θ=270∘\theta=270^\circ

270°.

Checks and common pitfalls: −90° is coterminal but outside the requested interval.

Think first. Reveal a hint when the class is ready.

11 / Standard#Your turn

Explain geometrically why sin(π−α)=sin α.

0<α<π/20<\alpha<\pi/2
  • α is acute and measured in radians.
Skills and prerequisite lessons

Scope: JM01 / JM02

Working and explanation

BUILD THE REASONING

Hint 1
Reflect across the y-axis.
Hint 2
Reflection preserves the vertical coordinate.
Worked solution
  1. Write the original unit-circle point.

    P=(cos⁡α,sin⁡α)P=(\cos\alpha,\sin\alpha)
  2. Reflect to angle π−α.

    Preflected=(−cos⁡α,sin⁡α)P_{\mathrm{reflected}}=(-\cos\alpha,\sin\alpha)

The equal y-coordinates prove the identity.

Checks and common pitfalls: This explains which coordinate changes sign instead of memorising a formula.

Reasoning checklist · self / teacher assessment
  • Write the original unit-circle point.
  • Reflect to angle π−α.

Think first. Reveal a hint when the class is ready.

12 / Transfer#Your turn

A point starts at (2,0) and rotates clockwise by 120° about the origin. Find its final height and position; explain the sign of the height.

r=2,θ=−120∘r=2,\quad\theta=-120^\circ
  • Rotation about the origin; positive y is upward.
Skills and prerequisite lessons

Scope: JM01 / JM02

Working and explanation

BUILD THE REASONING

Hint 1
Height is a signed vertical coordinate, not distance from the x-axis.
Hint 2
Use radius times the unit-circle coordinates.
Worked solution
  1. Determine the signed trigonometric values.

    cos⁡(−120∘)=−1/2,sin⁡(−120∘)=−3/2\cos(-120^\circ)=-1/2,\quad\sin(-120^\circ)=-\sqrt3/2
  2. Scale by the physical radius.

    P=(−1,−3)P=(-1,-\sqrt3)

Height −√3 and position (−1,−√3).

Checks and common pitfalls: The point lies below the axis after this clockwise turn; distance below it would be positive √3.

Reasoning checklist · self / teacher assessment
  • Determine the signed trigonometric values.
  • Scale by the physical radius.

Think first. Reveal a hint when the class is ready.

13 / Transfer#Your turn

Two exact readings claim sine=0.8 and cosine=0.8 for one angle. Decide whether any real angle fits and explain whether changing quadrant could repair them.

s=0.8,c=0.8s=0.8,\quad c=0.8
  • Readings are stated as exact, not rounded measurements.
Skills and prerequisite lessons

Scope: JM01 / JM02

Working and explanation

BUILD THE REASONING

Hint 1
Check the unit-circle norm before recovering an angle.
Hint 2
The squared readings sum to 1.28.
Worked solution
  1. Test the necessary identity.

    s2+c2=0.64+0.64=1.28≠1s^2+c^2=0.64+0.64=1.28\ne1
  2. Sign changes do not alter squared length.

    (±0.8)2+(±0.8)2=1.28(\pm0.8)^2+(\pm0.8)^2=1.28

No angle fits; changing quadrant cannot repair exact readings.

Checks and common pitfalls: This is a consistency test rather than an inverse-trig calculation.

Reasoning checklist · self / teacher assessment
  • Test the necessary identity.
  • Sign changes do not alter squared length.

Think first. Reveal a hint when the class is ready.

Focus on one question

End-of-lesson check and correction

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    Choose a foundation skill to revisit ↗

    Teacher preparation and assessment

    40-minute lesson

    MinutesFocusTeaching and student action
    5Signs and unitsUse diagnostics; require a marked unit-circle point.
    8Normalise a pointDerive cosine and sine from P=(−3,4), keeping signs.
    10Choose a branchPairs recover a missing coordinate from an identity and quadrant.
    12Model and rejectGroups compare clockwise height and impossible sensor readings.
    5Exit explanationAsk students to distinguish height from distance below the axis.

    Question sequence

    • Which coordinate does sine use?
    • What information chooses the sign after taking a square root?

    Board development

    • Normalise by a positive radius.
      (x,y)/r=(cos⁡θ,sin⁡θ)(x,y)/r=(\cos\theta,\sin\theta)
    • Check data before solving for an angle.
      s2+c2=1s^2+c^2=1

    Expected correct and incorrect responses

    • “Radius is positive, x is negative, so cosine is negative” is correct reasoning.
    • “Both readings are under 1, so they work” misses their joint constraint.

    Follow-up questions

    • Can a sign change repair an incorrect squared norm?

    Remediation

    • For sign errors, draw axes and project the point before recalling angle formulas.

    Exit check

    • For P=(5,−12), give sine and cosine with a sign reason. Expected −12/13 and 5/13.

    Assessment checklist and sample responses

    • 2 marks: coordinate normalisation.
      Full: divide signed coordinates by positive 13; partial: use unsigned lengths only.
    • 2 marks: model interpretation or consistency.
      Full: squared norm 1.28 rejects data in every quadrant; partial: says impossible without a test.

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    Curriculum and source notes ↗