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Software simplifies the quotient to 1 and draws an unbroken horizontal line. Explain exactly where this drawing overstates the original domain.

Read the idea, work independently, then explain what changed.

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高一必修 第一册(A版).pdf · 5.5 · PDF 222 / printed page 215

Revisit first: Unit-circle coordinates and signs

TOPIC 01

Identity choice and domain preservation

Transform expressions with a purpose, explain excluded angles and test tempting false rules.

What you will be able to explain

  • Choose an identity that matches the desired form.
  • Separate equality on a shared domain from extending a simplified formula.

Try it. Leave your reasoning visible.

Use one hint at a time. A correction explains what changed, not just the final answer.

Examples 1–3: study a full demonstration; finish a solution from its first step; then choose a method independently before opening the solution. The remaining exercises may continue after class.

01 / Transfer#Your turn

Software simplifies the quotient to 1 and draws an unbroken horizontal line. Explain exactly where this drawing overstates the original domain.

F(x)=(sin⁡x+cos⁡x)2−1sin⁡2xF(x)=\frac{(\sin x+\cos x)^2-1}{\sin2x}
  • x in radians; k any integer.
Skills and prerequisite lessons

Scope: JM01 / JM02

Working and explanation

BUILD THE REASONING

Hint 1
Expand the numerator before cancelling.
Hint 2
The numerator equals sin 2x, but its zeros were forbidden denominators.
Worked solution
  1. Verify the equality on the original domain.

    (sin⁡x+cos⁡x)2−1=2sin⁡xcos⁡x=sin⁡2x(\sin x+\cos x)^2-1=2\sin x\cos x=\sin2x
  2. Retain the excluded points in the graph.

    F(x)=1,x≠kπ/2F(x)=1,\quad x\ne k\pi/2

The line y=1 has holes at every x=kπ/2.

Checks and common pitfalls: A simplified expression is an extension if the original exclusions are erased.

Reasoning checklist · self / teacher assessment
  • Verify the equality on the original domain.
  • Retain the excluded points in the graph.

Think first. Reveal a hint when the class is ready.

Focus on one question

Teacher preparation and assessment

40-minute lesson

MinutesFocusTeaching and student action
5Test two claimsContrast false additivity with a domain hole using diagnostics.
8Choose a destinationStudents name the target form before using an identity.
10Track exclusionsPairs simplify the double-angle quotient and mark all forbidden angles.
12Prove a boundGroups construct the complementary square for the amplitude bound.
5Exit domainRequire formula plus exclusions, not just the simplified value.

Question sequence

  • Which feature of the target expression suggests this identity?
  • Does the operation preserve the domain?

Board development

  • Record restrictions before cancellation.
    sin⁡2x≠0\sin2x\ne0
  • Turn an identity into a bound.
    u2+v2=25u^2+v^2=25

Expected correct and incorrect responses

  • “The values agree where the original denominator is nonzero” correctly limits equality.
  • “It simplifies to 1 everywhere” incorrectly fills holes.

Follow-up questions

  • How do we prove the bound is attainable rather than merely valid?

Remediation

  • For false additivity, evaluate one concrete angle pair before teaching the correct expansion.

Exit check

  • Simplify sin²x/(1−cos²x) with its domain. Expected 1 for x≠kπ.

Assessment checklist and sample responses

  • 2 marks: justified identity choice.
    Full: numerator becomes sin²x matching the denominator; partial: unexplained cancellation.
  • 2 marks: domain and equality cases.
    Full: x≠kπ/2 retained; partial: only cosine zeros excluded.

No sign-in. Work stays in this browser. Export before clearing browser data. Written reasoning is assessed with a checklist.

Curriculum and source notes ↗