← Senior Mathematics Studio

LEARN · EXPLAIN · REVISE

Refute sine additivity with a=b=30°.

Read the idea, work independently, then explain what changed.

Return to the lesson / paper ↗

高一必修 第一册(A版).pdf · 5.5 · PDF 222 / printed page 215

Revisit first: Unit-circle coordinates and signs

TOPIC 01

Identity choice and domain preservation

Transform expressions with a purpose, explain excluded angles and test tempting false rules.

What you will be able to explain

  • Choose an identity that matches the desired form.
  • Separate equality on a shared domain from extending a simplified formula.

Try it. Leave your reasoning visible.

Use one hint at a time. A correction explains what changed, not just the final answer.

Examples 1–3: study a full demonstration; finish a solution from its first step; then choose a method independently before opening the solution. The remaining exercises may continue after class.

01 / Foundation#Your turn

Refute sine additivity with a=b=30°.

sin⁡(a+b)=sin⁡a+sin⁡b\sin(a+b)=\sin a+\sin b
  • Angles in degrees.
Skills and prerequisite lessons

Scope: JM01 / JM02

Working and explanation

BUILD THE REASONING

Hint 1
Calculate both sides independently.
Hint 2
The left angle is 60°, not 30°.
Worked solution
  1. Evaluate the left side.

    sin⁡60∘=3/2\sin60^\circ=\sqrt3/2
  2. Evaluate the right side and compare.

    1/2+1/2=1≠3/21/2+1/2=1\ne\sqrt3/2

The claim is false.

Checks and common pitfalls: One valid counterexample refutes a purported identity.

Reasoning checklist · self / teacher assessment
  • Evaluate the left side.
  • Evaluate the right side and compare.

Think first. Reveal a hint when the class is ready.

Focus on one question

Teacher preparation and assessment

40-minute lesson

MinutesFocusTeaching and student action
5Test two claimsContrast false additivity with a domain hole using diagnostics.
8Choose a destinationStudents name the target form before using an identity.
10Track exclusionsPairs simplify the double-angle quotient and mark all forbidden angles.
12Prove a boundGroups construct the complementary square for the amplitude bound.
5Exit domainRequire formula plus exclusions, not just the simplified value.

Question sequence

  • Which feature of the target expression suggests this identity?
  • Does the operation preserve the domain?

Board development

  • Record restrictions before cancellation.
    sin⁡2x≠0\sin2x\ne0
  • Turn an identity into a bound.
    u2+v2=25u^2+v^2=25

Expected correct and incorrect responses

  • “The values agree where the original denominator is nonzero” correctly limits equality.
  • “It simplifies to 1 everywhere” incorrectly fills holes.

Follow-up questions

  • How do we prove the bound is attainable rather than merely valid?

Remediation

  • For false additivity, evaluate one concrete angle pair before teaching the correct expansion.

Exit check

  • Simplify sin²x/(1−cos²x) with its domain. Expected 1 for x≠kπ.

Assessment checklist and sample responses

  • 2 marks: justified identity choice.
    Full: numerator becomes sin²x matching the denominator; partial: unexplained cancellation.
  • 2 marks: domain and equality cases.
    Full: x≠kπ/2 retained; partial: only cosine zeros excluded.

No sign-in. Work stays in this browser. Export before clearing browser data. Written reasoning is assessed with a checklist.

Curriculum and source notes ↗