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Add 2x+2√y+3z=a to the k=3 system. Find the largest possible a and the solution attaining it.

Read the idea, work independently, then explain what changed.

TOPIC 01

2024 JM02

The square root requires y=t≥0.

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Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

Add 2x+2√y+3z=a to the k=3 system. Find the largest possible a and the solution attaining it.

Official paper · jm02-2024 · 5(c) · PDF 7

Official original and suggested answers ↗ · Suggested answer PDF page 11

Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Substitute (x,y,z)=(1−2t,t,t) and require t≥0.
Hint 2
Complete a square in √t.
Worked solution
  1. Reduce the final equation with its domain.

    t≥0,a=2(1−2t)+2t+3t=2−t+2tt\ge0,\quad a=2(1-2t)+2\sqrt t+3t=2-t+2\sqrt t
  2. The square has minimum zero.

    a=3−(t−1)2≤3,a=3  ⟺  t=1a=3-(\sqrt t-1)^2\le3,\quad a=3\iff t=1
  3. Substitute the equality case.

    (x,y,z)=(−1,1,1)(x,y,z)=(-1,1,1)

Maximum a=3, attained only at (−1,1,1).

Checks and common pitfalls: The square root requires y=t≥0.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • Reduce the final equation with its domain.
    t≥0,a=2(1−2t)+2t+3t=2−t+2tt\ge0,\quad a=2(1-2t)+2\sqrt t+3t=2-t+2\sqrt t
  • The square has minimum zero.
    a=3−(t−1)2≤3,a=3  ⟺  t=1a=3-(\sqrt t-1)^2\le3,\quad a=3\iff t=1
  • Substitute the equality case.
    (x,y,z)=(−1,1,1)(x,y,z)=(-1,1,1)

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Curriculum and source notes ↗