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Simplify the principal square root.

Read the idea, work independently, then explain what changed.

TOPIC 01

2022 JM01

√(u²)=|u|, not automatically u.

Try it. Leave your reasoning visible.

Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

Simplify the principal square root.

7−43\sqrt{7-4\sqrt3}

Official paper · jm01-2022 · I.4 · PDF 2

Official original and suggested answers ↗ · Suggested answer PDF page 5

Skills and prerequisite lessons
  1. Option A3−2\sqrt3-\sqrt2
  2. Option B2−32-\sqrt3
  3. Option C3−2\sqrt3-2
  4. Option D2−62-\sqrt6
  5. Option E2−232-2\sqrt3

Working and explanation

BUILD THE REASONING

Hint 1
Recognise 7 as 4+3.
Hint 2
Check which sign gives a nonnegative number.
Worked solution
  1. Identify the perfect square.

    7−43=(2−3)27-4\sqrt3=(2-\sqrt3)^2
  2. Since 2>√3, the principal root is positive.

    (2−3)2=∣2−3∣=2−3\sqrt{(2-\sqrt3)^2}=|2-\sqrt3|=2-\sqrt3

B: 2−√3.

Checks and common pitfalls: √(u²)=|u|, not automatically u.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • Identify the perfect square.
    7−43=(2−3)27-4\sqrt3=(2-\sqrt3)^2
  • Since 2>√3, the principal root is positive.
    (2−3)2=∣2−3∣=2−3\sqrt{(2-\sqrt3)^2}=|2-\sqrt3|=2-\sqrt3

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Curriculum and source notes ↗