Model or definition
Find antiderivatives, evaluate definite integrals and distinguish signed accumulation from geometric area.
LEARN · EXPLAIN · REVISE
Read the idea, work independently, then explain what changed.
2027 JM02 考試大綱 · 6. Basic calculus: integrals and area · PDF 2 / printed page 2
Revisit first: Derivative operations
TOPIC 01
Find antiderivatives, evaluate definite integrals and distinguish signed accumulation from geometric area.
Find antiderivatives, evaluate definite integrals and distinguish signed accumulation from geometric area.
An indefinite integral includes an arbitrary constant; split at sign changes when calculating area. Revolution volumes are a school extension (T06 PDF6–10).
PREDICT → EXPLORE → EXPLAIN → TRANSFER
Lesson question: Can the signed integral be zero while the total area is positive?
Model exploration: predict which displayed result changes with the parameters, check the values, and compare the observation with the lesson question.
y=ax²; tangent slope at x=t is 2; signed integral from 0 to t is 0.3333. Signed integral can be negative.
Explain: Compare two admissible cases and explain their different results using the stated model.
Transfer: Compare x on a symmetric interval with |x| on that interval.
Use one hint at a time. A correction explains what changed, not just the final answer.
Working and explanation
BUILD THE REASONING
Write the defining equation, retain exclusions, and then solve or compare.
Apply the stated relation and retain its conditions.
The derivative check confirms the power and constant.
The requested relation or conclusion is shown below.
Checks and common pitfalls: The derivative check confirms the power and constant.
Think first. Reveal a hint when the class is ready.
Working and explanation
BUILD THE REASONING
Write the defining equation, retain exclusions, and then solve or compare.
Apply the stated relation and retain its conditions.
Top minus bottom is nonnegative throughout this interval.
The requested value is 4.5.
Checks and common pitfalls: Top minus bottom is nonnegative throughout this interval.
Think first. Reveal a hint when the class is ready.
Working and explanation
BUILD THE REASONING
Write the defining equation, retain exclusions, and then solve or compare.
Apply the stated relation and retain its conditions.
The squared radius enters disk area; integrating y alone would give area rather than volume.
The requested value is 67.0206432766.
Checks and common pitfalls: The squared radius enters disk area; integrating y alone would give area rather than volume.
Think first. Reveal a hint when the class is ready.
Working and explanation
BUILD THE REASONING
Write the defining equation, retain exclusions, and then solve or compare.
Apply the stated relation and retain its conditions.
The derivative check confirms the power and constant.
The requested relation or conclusion is shown below.
Checks and common pitfalls: The derivative check confirms the power and constant.
Think first. Reveal a hint when the class is ready.
Working and explanation
BUILD THE REASONING
Write the defining equation, retain exclusions, and then solve or compare.
Apply the stated relation and retain its conditions.
A definite integral has a value, not an arbitrary integration constant.
The requested value is 36.
Checks and common pitfalls: A definite integral has a value, not an arbitrary integration constant.
Think first. Reveal a hint when the class is ready.
Working and explanation
BUILD THE REASONING
Write the defining equation, retain exclusions, and then solve or compare.
Apply the stated relation and retain its conditions.
The two signed contributions cancel.
The requested value is 0.
Checks and common pitfalls: The two signed contributions cancel.
Think first. Reveal a hint when the class is ready.
Working and explanation
BUILD THE REASONING
Write the defining equation, retain exclusions, and then solve or compare.
Apply the stated relation and retain its conditions.
Use the absolute value of the integrand for area.
The requested value is 64.
Checks and common pitfalls: Use the absolute value of the integrand for area.
Think first. Reveal a hint when the class is ready.
Working and explanation
BUILD THE REASONING
Write the defining equation, retain exclusions, and then solve or compare.
Apply the stated relation and retain its conditions.
Use the absolute value of the integrand for area.
The requested value is 81.
Checks and common pitfalls: Use the absolute value of the integrand for area.
Think first. Reveal a hint when the class is ready.
Working and explanation
BUILD THE REASONING
Write the defining equation, retain exclusions, and then solve or compare.
Apply the stated relation and retain its conditions.
Top minus bottom is nonnegative throughout this interval.
The requested value is 50.
Checks and common pitfalls: Top minus bottom is nonnegative throughout this interval.
Think first. Reveal a hint when the class is ready.
Working and explanation
BUILD THE REASONING
Write the defining equation, retain exclusions, and then solve or compare.
Apply the stated relation and retain its conditions.
Apply the stated relation and retain its conditions.
An initial condition fixes the integration constant.
The requested value is 15.
Checks and common pitfalls: An initial condition fixes the integration constant.
Think first. Reveal a hint when the class is ready.
Working and explanation
BUILD THE REASONING
Write the defining equation, retain exclusions, and then solve or compare.
Apply the stated relation and retain its conditions.
The squared radius enters disk area; integrating y alone would give area rather than volume.
The requested value is 1809.55736847.
Checks and common pitfalls: The squared radius enters disk area; integrating y alone would give area rather than volume.
Think first. Reveal a hint when the class is ready.
Working and explanation
BUILD THE REASONING
Write the defining equation, retain exclusions, and then solve or compare.
Apply the stated relation and retain its conditions.
Apply the stated relation and retain its conditions.
An initial condition fixes the integration constant.
The requested value is 17.
Checks and common pitfalls: An initial condition fixes the integration constant.
Think first. Reveal a hint when the class is ready.
Working and explanation
BUILD THE REASONING
Write the defining equation, retain exclusions, and then solve or compare.
Apply the stated relation and retain its conditions.
The squared radius enters disk area; integrating y alone would give area rather than volume.
The requested value is 2873.51008048.
Checks and common pitfalls: The squared radius enters disk area; integrating y alone would give area rather than volume.
Think first. Reveal a hint when the class is ready.
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