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A cosine curve has a maximum of 8 at x = 0, a minimum of 2, and successive maxima 4π apart. With x in radians, which equation fits all three features?

Read the idea, work independently, then explain what changed.

TOPIC 01

Trigonometric ratios and function graphs

B confuses amplitude with the full vertical span; C uses the wrong period; D starts at the minimum. Each stated feature helps rule out a different error.

PREDICT → MOVE → EXPLAIN

See amplitude, period and phase together.

Predict the number of cycles and the horizontal shift. Switch angle units without changing the curve.

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Try it. Leave your reasoning visible.

Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Transfer#Your turn

A cosine curve has a maximum of 8 at x = 0, a minimum of 2, and successive maxima 4π apart. With x in radians, which equation fits all three features?

  1. First modely=3cos⁡(x2)+5y=3\cos\left(\frac x2\right)+5
  2. Second modely=6cos⁡(x2)+2y=6\cos\left(\frac x2\right)+2
  3. Third modely=3cos⁡(2x)+5y=3\cos(2x)+5
  4. Fourth modely=−3cos⁡(x2)+5y=-3\cos\left(\frac x2\right)+5

Working and explanation

BUILD THE REASONING

Hint 1
The midline is halfway between the largest and smallest values; amplitude is half their difference.
Hint 2
Use T = 2π/B with positive B, then check whether x = 0 is a maximum or a minimum.
Worked solution
  1. Recover the vertical parameters.

    D=8+22=5,A=8−22=3D=\frac{8+2}{2}=5,\qquad A=\frac{8-2}{2}=3
  2. Recover the horizontal multiplier from the period.

    B=2π4π=12B=\frac{2\pi}{4\pi}=\frac12
  3. A positive cosine coefficient gives the required initial peak.

    y(0)=3cos⁡0+5=8y(0)=3\cos0+5=8

A: y = 3 cos(x/2) + 5.

Checks and common pitfalls: B confuses amplitude with the full vertical span; C uses the wrong period; D starts at the minimum. Each stated feature helps rule out a different error.

Think first. Reveal a hint when the class is ready.

Focus on one question

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Curriculum and source notes ↗