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Find the squared radius of the circle with diameter endpoints A and B.

Read the idea, work independently, then explain what changed.

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高二選擇性必修 第一册(A版).pdf · 2.4 · PDF 87 / printed page 82

Revisit first: Intersections and distance formulas

TOPIC 01

Equations of a circle

Construct circle equations from centers, radii, diameters and point constraints.

What you will be able to explain

  • Construct circle equations from centers, radii, diameters and point constraints.
  • Justify the method and check the conditions in a new situation.

Try it. Leave your reasoning visible.

Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Foundation#Your turn

Find the squared radius of the circle with diameter endpoints A and B.

A=(0,0),B=(14,4)A=(0,0),\quad B=(14,4)
  • In x²+y²+Dx+Ey+F=0, a nondegenerate circle requires (D²+E²)/4−F>0.
Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Translate the geometric condition into a coordinate equation.
Hint 2
Use this intermediate relation.
r2=AB2/4r^2=AB^2/4
Worked solution
  1. Translate the geometric condition into a coordinate equation.

  2. Apply the stated relation and retain its conditions.

    AB2=(2⋅7)2+42AB^2=(2\cdot7)^2+4^2
  3. Apply the stated relation and retain its conditions.

    r2=53r^2=53
  4. The radius is half the diameter, so its square is one quarter.

The requested value is 53.

Checks and common pitfalls: The radius is half the diameter, so its square is one quarter.

Think first. Reveal a hint when the class is ready.

Focus on one question

Teacher preparation and assessment

Question sequence

  • Construct circle equations from centers, radii, diameters and point constraints.
  • Which condition is essential in equations of a circle?
  • Predict the shape when the constant of a circle equation changes through the zero-radius threshold.

Board plan

  • Standard form: A circle is the locus at fixed positive distance from its center.
    (x−h)2+(y−k)2=r2(x-h)^2+(y-k)^2=r^2
  • Existence: In x²+y²+Dx+Ey+F=0, a nondegenerate circle requires (D²+E²)/4−F>0.

Anticipated thinking

  • A positive squared radius is necessary; zero gives a single point, and negative gives no real locus.

Assessment checklist

  • 1 mark: choose the correct representation and conditions.
  • 1 mark: establish the intermediate relation.
  • 1 mark: complete a connected calculation or proof.
  • 1 mark: interpret and check the conclusion.

No sign-in. Work stays in this browser. Export before clearing browser data. Written reasoning is assessed with a checklist.

Curriculum and source notes ↗