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Let α and β be the roots. Find the sum of their squares without calculating the individual roots.

Read the idea, work independently, then explain what changed.

TOPIC 01

Quadratic equations and functions

Squaring the sum introduces 2αβ. Leaving that term in would give 25, which is not the sum of the squares.

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What does each coefficient change?

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Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Transfer#Your turn

Let α and β be the roots. Find the sum of their squares without calculating the individual roots.

x2−5x+2=0,α2+β2=?x^2-5x+2=0,\qquad \alpha^2+\beta^2=?

Working and explanation

BUILD THE REASONING

Hint 1
Read the sum and product of the roots from the coefficients.
Hint 2
Expand (α + β)², then subtract the cross term.
Worked solution
  1. Use the relationships between roots and coefficients.

    α+β=5,αβ=2\alpha+\beta=5,\qquad \alpha\beta=2
  2. Express the required quantity using that sum and product.

    α2+β2=(α+β)2−2αβ=25−4=21\alpha^2+\beta^2=(\alpha+\beta)^2-2\alpha\beta=25-4=21

The sum of the squares is 21.

Checks and common pitfalls: Squaring the sum introduces 2αβ. Leaving that term in would give 25, which is not the sum of the squares.

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Curriculum and source notes ↗