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Which pair gives all the roots?

Read the idea, work independently, then explain what changed.

TOPIC 01

Quadratic equations and functions

Their sum is 7/2 and product is 3/2, agreeing with −b/a and c/a. Both values also give zero on substitution.

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What does each coefficient change?

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01 / Standard#Your turn

Which pair gives all the roots?

2x2−7x+3=02x^2-7x+3=0
  1. First pairx=−3, −12x=-3,\ -\tfrac12
  2. Second pairx=1, 3x=1,\ 3
  3. Third pairx=12, 3x=\tfrac12,\ 3
  4. Fourth pairx=2, 32x=2,\ \tfrac32

Working and explanation

BUILD THE REASONING

Hint 1
Look for two factors whose product is 2x² − 7x + 3.
Hint 2
Try factors with first terms 2x and x, and constants −1 and −3.
Worked solution
  1. Factor the quadratic.

    2x2−7x+3=(2x−1)(x−3)2x^2-7x+3=(2x-1)(x-3)
  2. A product is zero when at least one factor is zero.

    2x−1=0 or x−3=0⇒x=12 or 32x-1=0\ \text{or}\ x-3=0\Rightarrow x=\tfrac12\ \text{or}\ 3

C: the roots are 1/2 and 3.

Checks and common pitfalls: Their sum is 7/2 and product is 3/2, agreeing with −b/a and c/a. Both values also give zero on substitution.

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