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Give the complete real solution set of the two linear equations.

Read the idea, work independently, then explain what changed.

TOPIC 01

2026 JM02

Two independent equations in three unknowns leave one free parameter.

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Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

Give the complete real solution set of the two linear equations.

x+y+z=2,3x+y−z=4x+y+z=2,\quad3x+y-z=4

Official paper · jm02-2026 · 5(b)(i) · PDF 7

Official original and suggested answers ↗ · Suggested answer PDF page 11

Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Subtract the first equation from the second.
Hint 2
Choose z as the free real parameter.
Worked solution
  1. Elimination gives the relation between x and z.

    2x−2z=2  ⟹  x=z+12x-2z=2\implies x=z+1
  2. Set z=t and recover y from the first equation.

    (x,y,z)=(1+t,1−2t,t),t∈R(x,y,z)=(1+t,1-2t,t),\quad t\in\mathbb R

(x,y,z)=(1+t,1−2t,t), t∈ℝ.

Checks and common pitfalls: Two independent equations in three unknowns leave one free parameter.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • Elimination gives the relation between x and z.
    2x−2z=2  ⟹  x=z+12x-2z=2\implies x=z+1
  • Set z=t and recover y from the first equation.
    (x,y,z)=(1+t,1−2t,t),t∈R(x,y,z)=(1+t,1-2t,t),\quad t\in\mathbb R

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Curriculum and source notes ↗