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Find both roots in unit polar form with principal argument in (−π,π].

Read the idea, work independently, then explain what changed.

TOPIC 01

2026 JM02

The ± sign changes the sine term as well as the angle.

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Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

Find both roots in unit polar form with principal argument in (−π,π].

z2−3z+1=0z^2-\sqrt3z+1=0

Official paper · jm02-2026 · 4(a)(i) · PDF 6

Official original and suggested answers ↗ · Suggested answer PDF page 10

Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Use the quadratic formula over the complex numbers.
Hint 2
Both roots have modulus one.
Worked solution
  1. The discriminant is −1.

    z=3±i2z=\frac{\sqrt3\pm i}{2}
  2. Identify cosine and sine coordinates on the unit circle.

    z=cos⁡(±π6)+isin⁡(±π6)z=\cos\left(\pm\frac\pi6\right)+i\sin\left(\pm\frac\pi6\right)

Arguments π/6 and −π/6, both of modulus one.

Checks and common pitfalls: The ± sign changes the sine term as well as the angle.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • The discriminant is −1.
    z=3±i2z=\frac{\sqrt3\pm i}{2}
  • Identify cosine and sine coordinates on the unit circle.
    z=cos⁡(±π6)+isin⁡(±π6)z=\cos\left(\pm\frac\pi6\right)+i\sin\left(\pm\frac\pi6\right)

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Curriculum and source notes ↗