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Find the nonreal cube roots of eight.

Read the idea, work independently, then explain what changed.

TOPIC 01

2025 JM02

The root 2 must be excluded because the imaginary part is nonzero.

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Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

Find the nonreal cube roots of eight.

z=a+bi,a,b∈R, b≠0,z3=8z=a+bi,\quad a,b\in\mathbb R,\ b\ne0,\quad z^3=8

Official paper · jm02-2025 · 4(a) · PDF 6

Official original and suggested answers ↗ · Suggested answer PDF page 10

Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Factor z³−8.
Hint 2
Discard the real root before solving the quadratic factor.
Worked solution
  1. Use the difference-of-cubes identity.

    z3−8=(z−2)(z2+2z+4)z^3-8=(z-2)(z^2+2z+4)
  2. The root 2 violates b≠0; solve the other factor.

    z=−1±3iz=-1\pm\sqrt3i

z=−1±√3i.

Checks and common pitfalls: The root 2 must be excluded because the imaginary part is nonzero.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • Use the difference-of-cubes identity.
    z3−8=(z−2)(z2+2z+4)z^3-8=(z-2)(z^2+2z+4)
  • The root 2 violates b≠0; solve the other factor.
    z=−1±3iz=-1\pm\sqrt3i

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Curriculum and source notes ↗