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Find the inflection point and verify the concavity change.

Read the idea, work independently, then explain what changed.

TOPIC 01

2025 JM02

An inflection concerns concavity, not necessarily a stationary point.

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Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

Find the inflection point and verify the concavity change.

f(x)=x3+3x2−4f(x)=x^3+3x^2-4

Official paper · jm02-2025 · 2(a)(iv) · PDF 4

Official original and suggested answers ↗ · Suggested answer PDF page 9

Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Solve 6x+6=0.
Hint 2
Substitute the resulting x into f.
Worked solution
  1. The second derivative changes from negative to positive at −1.

    f′′(x)=6(x+1)f''(x)=6(x+1)
  2. Evaluate its ordinate.

    f(−1)=−1+3−4=−2f(-1)=-1+3-4=-2

Inflection point (−1,−2).

Checks and common pitfalls: An inflection concerns concavity, not necessarily a stationary point.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • The second derivative changes from negative to positive at −1.
    f′′(x)=6(x+1)f''(x)=6(x+1)
  • Evaluate its ordinate.
    f(−1)=−1+3−4=−2f(-1)=-1+3-4=-2

Think first. Reveal a hint when the class is ready.

Focus on one question

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Curriculum and source notes ↗