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Factor the determinant.

Read the idea, work independently, then explain what changed.

TOPIC 01

2024 JM02

The cofactor in position (2,1) carries a minus sign.

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Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

Factor the determinant.

D=∣abcb+cc+aa+b1+b1+c1+a∣D=\begin{vmatrix}a&b&c\\b+c&c+a&a+b\\1+b&1+c&1+a\end{vmatrix}

Official paper · jm02-2024 · 5(a) · PDF 7

Official original and suggested answers ↗ · Suggested answer PDF page 11

Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Add row 1 to row 2.
Hint 2
Factor a+b+c and then subtract column 1 from columns 2 and 3.
Worked solution
  1. The second row becomes constant.

    D=(a+b+c)∣abc1111+b1+c1+a∣D=(a+b+c)\begin{vmatrix}a&b&c\\1&1&1\\1+b&1+c&1+a\end{vmatrix}
  2. Column differences make expansion along row 2 simple.

    D=−(a+b+c)∣b−ac−ac−ba−b∣D=-(a+b+c)\begin{vmatrix}b-a&c-a\\c-b&a-b\end{vmatrix}
  3. Expand and collect the quadratic factor.

    D=(a+b+c)(a2+b2+c2−ab−bc−ca)D=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)

(a+b+c)(a²+b²+c²−ab−bc−ca).

Checks and common pitfalls: The cofactor in position (2,1) carries a minus sign.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • The second row becomes constant.
    D=(a+b+c)∣abc1111+b1+c1+a∣D=(a+b+c)\begin{vmatrix}a&b&c\\1&1&1\\1+b&1+c&1+a\end{vmatrix}
  • Column differences make expansion along row 2 simple.
    D=−(a+b+c)∣b−ac−ac−ba−b∣D=-(a+b+c)\begin{vmatrix}b-a&c-a\\c-b&a-b\end{vmatrix}
  • Expand and collect the quadratic factor.
    D=(a+b+c)(a2+b2+c2−ab−bc−ca)D=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)

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Curriculum and source notes ↗