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Find all real solutions.

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TOPIC 01

2024 JM02

Dividing by sine or cosine would discard a whole solution family.

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Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

Find all real solutions.

2cos⁡α−cos⁡3α−cos⁡5α=02\cos\alpha-\cos3\alpha-\cos5\alpha=0

Official paper · jm02-2024 · 4(c) · PDF 6

Official original and suggested answers ↗ · Suggested answer PDF page 11

Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Use the product identity from part (b).
Hint 2
A product is zero when at least one factor is zero.
Worked solution
  1. Reduce to sine and cosine zeros.

    16sin⁡2αcos⁡3α=0  ⟺  sin⁡α=0 or cos⁡α=016\sin^2\alpha\cos^3\alpha=0\iff\sin\alpha=0\ \text{or}\ \cos\alpha=0
  2. Merge the two families.

    α=kπ or α=π/2+kπ  ⟺  α=nπ/2, n∈Z\alpha=k\pi\ \text{or}\ \alpha=\pi/2+k\pi\iff\alpha=n\pi/2,\ n\in\mathbb Z

α=nπ/2, n∈ℤ.

Checks and common pitfalls: Dividing by sine or cosine would discard a whole solution family.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • Reduce to sine and cosine zeros.
    16sin⁡2αcos⁡3α=0  ⟺  sin⁡α=0 or cos⁡α=016\sin^2\alpha\cos^3\alpha=0\iff\sin\alpha=0\ \text{or}\ \cos\alpha=0
  • Merge the two families.
    α=kπ or α=π/2+kπ  ⟺  α=nπ/2, n∈Z\alpha=k\pi\ \text{or}\ \alpha=\pi/2+k\pi\iff\alpha=n\pi/2,\ n\in\mathbb Z

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Curriculum and source notes ↗