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Find z²⁶ in Cartesian form.

Read the idea, work independently, then explain what changed.

TOPIC 01

2024 JM02

The modulus is (√2)²⁶=2¹³, not 2²⁶.

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Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

Find z²⁶ in Cartesian form.

z=3+i1+iz=\frac{\sqrt3+i}{1+i}

Official paper · jm02-2024 · 4(a)(ii) · PDF 6

Official original and suggested answers ↗ · Suggested answer PDF page 10

Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Raise the modulus to 26 and multiply the argument by 26.
Hint 2
Reduce −13π/6 modulo 2π.
Worked solution
  1. Apply De Moivre’s theorem.

    z26=213cis⁡(−13π/6)=213cis⁡(−π/6)z^{26}=2^{13}\operatorname{cis}(-13\pi/6)=2^{13}\operatorname{cis}(-\pi/6)
  2. Evaluate the exact trigonometric values.

    z26=2123−212iz^{26}=2^{12}\sqrt3-2^{12}i

4096√3−4096i.

Checks and common pitfalls: The modulus is (√2)²⁶=2¹³, not 2²⁶.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • Apply De Moivre’s theorem.
    z26=213cis⁡(−13π/6)=213cis⁡(−π/6)z^{26}=2^{13}\operatorname{cis}(-13\pi/6)=2^{13}\operatorname{cis}(-\pi/6)
  • Evaluate the exact trigonometric values.
    z26=2123−212iz^{26}=2^{12}\sqrt3-2^{12}i

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Curriculum and source notes ↗