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A,B,C,D are coplanar as in the official diagram, with B and D on opposite sides of AC. ABC is equilateral; PAD is right isosceles at A; ∠PAC=π/2, ∠PCA=π/6, PA=1 and CD=2. Find the volume of PBCD.

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TOPIC 01

2024 JM02

The relative positions in the diagram determine that the two angles add.

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Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

A,B,C,D are coplanar as in the official diagram, with B and D on opposite sides of AC. ABC is equilateral; PAD is right isosceles at A; ∠PAC=π/2, ∠PCA=π/6, PA=1 and CD=2. Find the volume of PBCD.

Official paper · jm02-2024 · 1(b) · PDF 3

Official original and suggested answers ↗ · Suggested answer PDF page 8

Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
PA is perpendicular to the base plane because it is perpendicular to AC and AD.
Hint 2
Add the adjacent angles DCA and ACB.
Worked solution
  1. The base triangle is right at C.

    sin⁡∠DCA=1/2  ⟹  ∠DCA=π/6,∠DCB=π/6+π/3=π/2\sin\angle DCA=1/2\implies\angle DCA=\pi/6,\quad\angle DCB=\pi/6+\pi/3=\pi/2
  2. Use base area and perpendicular height.

    [BCD]=12(2)(3)=3,V=13[BCD] PA=33[BCD]=\frac12(2)(\sqrt3)=\sqrt3,\quad V=\frac13[BCD]\,PA=\frac{\sqrt3}3

Volume √3/3.

Checks and common pitfalls: The relative positions in the diagram determine that the two angles add.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • The base triangle is right at C.
    sin⁡∠DCA=1/2  ⟹  ∠DCA=π/6,∠DCB=π/6+π/3=π/2\sin\angle DCA=1/2\implies\angle DCA=\pi/6,\quad\angle DCB=\pi/6+\pi/3=\pi/2
  • Use base area and perpendicular height.
    [BCD]=12(2)(3)=3,V=13[BCD] PA=33[BCD]=\frac12(2)(\sqrt3)=\sqrt3,\quad V=\frac13[BCD]\,PA=\frac{\sqrt3}3

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Curriculum and source notes ↗