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Derive the two difference-to-product identities from the angle addition and subtraction formulae.

Read the idea, work independently, then explain what changed.

TOPIC 01

2023 JM02

The cosine difference identity has a leading minus sign.

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Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

Derive the two difference-to-product identities from the angle addition and subtraction formulae.

sin⁡x−sin⁡y=2cos⁡x+y2sin⁡x−y2,cos⁡x−cos⁡y=−2sin⁡x+y2sin⁡x−y2\sin x-\sin y=2\cos\frac{x+y}2\sin\frac{x-y}2,\quad\cos x-\cos y=-2\sin\frac{x+y}2\sin\frac{x-y}2

Official paper · jm02-2023 · 5(a)(i) · PDF 7

Official original and suggested answers ↗ · Suggested answer PDF page 11

Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Set u=(x+y)/2 and v=(x−y)/2.
Hint 2
Subtract the expansions at u+v and u−v.
Worked solution
  1. For sine, the sin u cos v terms cancel.

    sin⁡(u+v)−sin⁡(u−v)=2cos⁡usin⁡v\sin(u+v)-\sin(u-v)=2\cos u\sin v
  2. For cosine, the cos u cos v terms cancel. Substitute u,v back.

    cos⁡(u+v)−cos⁡(u−v)=−2sin⁡usin⁡v\cos(u+v)-\cos(u-v)=-2\sin u\sin v

Both identities follow by addition-formula cancellation.

Checks and common pitfalls: The cosine difference identity has a leading minus sign.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • For sine, the sin u cos v terms cancel.
    sin⁡(u+v)−sin⁡(u−v)=2cos⁡usin⁡v\sin(u+v)-\sin(u-v)=2\cos u\sin v
  • For cosine, the cos u cos v terms cancel. Substitute u,v back.
    cos⁡(u+v)−cos⁡(u−v)=−2sin⁡usin⁡v\cos(u+v)-\cos(u-v)=-2\sin u\sin v

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Curriculum and source notes ↗