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For the two roots m₁,m₂ of the slope quadratic, derive their sum and product.

Read the idea, work independently, then explain what changed.

TOPIC 01

2023 JM02

When h=±3 the slope equation is not quadratic.

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Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

For the two roots m₁,m₂ of the slope quadratic, derive their sum and product.

x29+y24=1,A=(h,k) outside the ellipse\frac{x^2}{9}+\frac{y^2}{4}=1,\quad A=(h,k)\text{ outside the ellipse}

Official paper · jm02-2023 · 3(a)(ii) · PDF 5

Official original and suggested answers ↗ · Suggested answer PDF page 9

Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Expand the tangent condition in powers of m.
Hint 2
Apply Vieta with h²≠9.
Worked solution
  1. Form the genuine quadratic assumed in this subpart.

    (9−h2)m2+2hkm+4−k2=0,h2≠9(9-h^2)m^2+2hkm+4-k^2=0,\quad h^2\ne9
  2. Read the two symmetric functions.

    m1+m2=2hkh2−9,m1m2=k2−4h2−9m_1+m_2=\frac{2hk}{h^2-9},\quad m_1m_2=\frac{k^2-4}{h^2-9}

Sum 2hk/(h²−9); product (k²−4)/(h²−9).

Checks and common pitfalls: When h=±3 the slope equation is not quadratic.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • Form the genuine quadratic assumed in this subpart.
    (9−h2)m2+2hkm+4−k2=0,h2≠9(9-h^2)m^2+2hkm+4-k^2=0,\quad h^2\ne9
  • Read the two symmetric functions.
    m1+m2=2hkh2−9,m1m2=k2−4h2−9m_1+m_2=\frac{2hk}{h^2-9},\quad m_1m_2=\frac{k^2-4}{h^2-9}

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Curriculum and source notes ↗