← Senior Mathematics Studio

LEARN · EXPLAIN · REVISE

Find the inflection point of y=f(x).

Read the idea, work independently, then explain what changed.

TOPIC 01

2021 JM02

An inflection requires a concavity change; f″=0 alone is insufficient.

Try it. Leave your reasoning visible.

Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

Find the inflection point of y=f(x).

f(x)=2x3−9x2+12x−5f(x)=2x^3-9x^2+12x-5

Official paper · jm02-2021 · 2(a)(iii) · PDF 4

Official original and suggested answers ↗ · Suggested answer PDF page 8

Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Solve f″(x)=0.
Hint 2
Check that concavity changes there.
Worked solution
  1. The second derivative vanishes at 3/2.

    12x−18=0  ⟹  x=3212x-18=0\implies x=\tfrac32
  2. It changes from negative to positive; evaluate the ordinate.

    x<32:f′′<0;x>32:f′′>0;f(32)=−12x<\tfrac32:f''<0;\quad x>\tfrac32:f''>0;\quad f(\tfrac32)=-\tfrac12

Inflection point (3/2,−1/2).

Checks and common pitfalls: An inflection requires a concavity change; f″=0 alone is insufficient.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • The second derivative vanishes at 3/2.
    12x−18=0  ⟹  x=3212x-18=0\implies x=\tfrac32
  • It changes from negative to positive; evaluate the ordinate.
    x<32:f′′<0;x>32:f′′>0;f(32)=−12x<\tfrac32:f''<0;\quad x>\tfrac32:f''>0;\quad f(\tfrac32)=-\tfrac12

Think first. Reveal a hint when the class is ready.

Focus on one question

No sign-in. Work stays in this browser. Export before clearing browser data. Written reasoning is assessed with a checklist.

Curriculum and source notes ↗