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For M on the x-axis, minimise PM+QM using P=(0,5), Q=(2,9), and find M.

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TOPIC 01

2026 JM01

Connecting P directly to Q does not cross the x-axis and cannot realise the constrained path.

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01 / Standard#Your turn

For M on the x-axis, minimise PM+QM using P=(0,5), Q=(2,9), and find M.

Official paper · jm01-2026 · II.2(b) · PDF 4

Official original and suggested answers ↗ · Suggested answer PDF page 7

Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Reflect one endpoint across the x-axis.
Hint 2
Use the straight segment from the reflected point to the other endpoint.
Worked solution
  1. Reflect P to P′; distances to points on the x-axis are unchanged.

    P′=(0,−5),PM=P′M,P′M+MQ≥P′QP'=(0,-5),\quad PM=P'M,\quad P'M+MQ\ge P'Q
  2. Equality holds where the segment crosses the axis.

    P′Q: y=7x−5,M=(57,0)P'Q:\ y=7x-5,\quad M=\left(\frac57,0\right)
  3. Compute the straight-line distance.

    min⁡(PM+QM)=22+142=102\min(PM+QM)=\sqrt{2^2+14^2}=10\sqrt2

Minimum 10√2, attained at M=(5/7,0).

Checks and common pitfalls: Connecting P directly to Q does not cross the x-axis and cannot realise the constrained path.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • Reflect P to P′; distances to points on the x-axis are unchanged.
    P′=(0,−5),PM=P′M,P′M+MQ≥P′QP'=(0,-5),\quad PM=P'M,\quad P'M+MQ\ge P'Q
  • Equality holds where the segment crosses the axis.
    P′Q: y=7x−5,M=(57,0)P'Q:\ y=7x-5,\quad M=\left(\frac57,0\right)
  • Compute the straight-line distance.
    min⁡(PM+QM)=22+142=102\min(PM+QM)=\sqrt{2^2+14^2}=10\sqrt2

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Curriculum and source notes ↗