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Team B also has three independent shots, each with probability 3/4. Find the probability that the total score is three and B beats A.

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TOPIC 01

2026 JM01

Total score three alone would also include pairs where A wins.

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01 / Standard#Your turn

Team B also has three independent shots, each with probability 3/4. Find the probability that the total score is three and B beats A.

Official paper · jm01-2026 · II.1(b) · PDF 4

Official original and suggested answers ↗ · Suggested answer PDF page 7

Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
List score pairs (A,B) satisfying both conditions.
Hint 2
Only (0,3) and (1,2) qualify.
Worked solution
  1. Find B’s probabilities with the binomial formula.

    P(B=3)=2764,P(B=2)=(32)(34)214=2764P(B=3)=\frac{27}{64},\quad P(B=2)=\binom32\left(\frac34\right)^2\frac14=\frac{27}{64}
  2. Independence allows multiplication; the two disjoint cases are then added.

    P=1242764+142764=63512P=\frac1{24}\frac{27}{64}+\frac14\frac{27}{64}=\frac{63}{512}

63/512.

Checks and common pitfalls: Total score three alone would also include pairs where A wins.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • Find B’s probabilities with the binomial formula.
    P(B=3)=2764,P(B=2)=(32)(34)214=2764P(B=3)=\frac{27}{64},\quad P(B=2)=\binom32\left(\frac34\right)^2\frac14=\frac{27}{64}
  • Independence allows multiplication; the two disjoint cases are then added.
    P=1242764+142764=63512P=\frac1{24}\frac{27}{64}+\frac14\frac{27}{64}=\frac{63}{512}

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Curriculum and source notes ↗