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Express log base b of ab using x.

Read the idea, work independently, then explain what changed.

TOPIC 01

2026 JM01

x=1 would force b=1, which is not a logarithm base.

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01 / Standard#Your turn

Express log base b of ab using x.

log⁡a(ab)=x\log_a(ab)=x

Official paper · jm01-2026 · I.7 · PDF 2

Official original and suggested answers ↗ · Suggested answer PDF page 6

Skills and prerequisite lessons
  1. Option Axx+1\frac{x}{x+1}
  2. Option Bxx−1\frac{x}{x-1}
  3. Option C1x\frac1x
  4. Option Dx1−x\frac{x}{1-x}
  5. None of these

Working and explanation

BUILD THE REASONING

Hint 1
First isolate log base a of b.
Hint 2
Change the base of the requested logarithm to a.
Worked solution
  1. The logarithms require positive bases different from one.

    a,b>0, a,b≠1,log⁡ab=x−1≠0a,b>0,\ a,b\ne1,\quad\log_a b=x-1\ne0
  2. Use change of base.

    log⁡b(ab)=log⁡a(ab)log⁡ab=xx−1\log_b(ab)=\frac{\log_a(ab)}{\log_a b}=\frac{x}{x-1}

B: x/(x−1).

Checks and common pitfalls: x=1 would force b=1, which is not a logarithm base.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • The logarithms require positive bases different from one.
    a,b>0, a,b≠1,log⁡ab=x−1≠0a,b>0,\ a,b\ne1,\quad\log_a b=x-1\ne0
  • Use change of base.
    log⁡b(ab)=log⁡a(ab)log⁡ab=xx−1\log_b(ab)=\frac{\log_a(ab)}{\log_a b}=\frac{x}{x-1}

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Curriculum and source notes ↗