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Find the sum of the squared roots without solving the quadratic.

Read the idea, work independently, then explain what changed.

TOPIC 01

2026 JM01

The middle term is 2αβ, not αβ.

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Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

Find the sum of the squared roots without solving the quadratic.

2x2−5x+1=0,roots α,β2x^2-5x+1=0,\quad\text{roots }\alpha,\beta

Official paper · jm01-2026 · I.6 · PDF 2

Official original and suggested answers ↗ · Suggested answer PDF page 6

Skills and prerequisite lessons
  1. Option A14\frac14
  2. Option B34\frac34
  3. Option C214\frac{21}4
  4. Option D234\frac{23}4
  5. Option E254\frac{25}4

Working and explanation

BUILD THE REASONING

Hint 1
Use the sum and product of roots.
Hint 2
Expand the square of the sum.
Worked solution
  1. Vieta gives both quantities.

    α+β=52,αβ=12\alpha+\beta=\frac52,\quad\alpha\beta=\frac12
  2. Subtract twice the product.

    α2+β2=(α+β)2−2αβ=254−1=214\alpha^2+\beta^2=(\alpha+\beta)^2-2\alpha\beta=\frac{25}4-1=\frac{21}4

C: 21/4.

Checks and common pitfalls: The middle term is 2αβ, not αβ.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • Vieta gives both quantities.
    α+β=52,αβ=12\alpha+\beta=\frac52,\quad\alpha\beta=\frac12
  • Subtract twice the product.
    α2+β2=(α+β)2−2αβ=254−1=214\alpha^2+\beta^2=(\alpha+\beta)^2-2\alpha\beta=\frac{25}4-1=\frac{21}4

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Curriculum and source notes ↗