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Find the parameter range making the function strictly decreasing on (−1,∞).

Read the idea, work independently, then explain what changed.

TOPIC 01

2026 JM01

Equality is allowed: the interval excludes −1.

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Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

Find the parameter range making the function strictly decreasing on (−1,∞).

f(x)=−3x2+2(a−1)x+2f(x)=-3x^2+2(a-1)x+2

Official paper · jm01-2026 · I.14 · PDF 3

Official original and suggested answers ↗ · Suggested answer PDF page 6

Skills and prerequisite lessons
  1. Option A[−2,∞)[-2,\infty)
  2. Option B(−∞,−2](-\infty,-2]
  3. Option C[−1,∞)[-1,\infty)
  4. Option D(−∞,−1](-\infty,-1]
  5. Option E[−2,−1][-2,-1]

Working and explanation

BUILD THE REASONING

Hint 1
Translate the condition on pairs of points into strict decrease.
Hint 2
The vertex of this downward parabola must be at or left of −1.
Worked solution
  1. Write the vertex coordinate.

    xv=a−13x_v=\frac{a-1}3
  2. To be decreasing throughout the open interval, the vertex may equal its left endpoint.

    a−13≤−1  ⟺  a≤−2\frac{a-1}3\le-1\iff a\le-2

B: a≤−2.

Checks and common pitfalls: Equality is allowed: the interval excludes −1.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • Write the vertex coordinate.
    xv=a−13x_v=\frac{a-1}3
  • To be decreasing throughout the open interval, the vertex may equal its left endpoint.
    a−13≤−1  ⟺  a≤−2\frac{a-1}3\le-1\iff a\le-2

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Curriculum and source notes ↗