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Find a₅+a₇ for the geometric sequence with the two given constraints.

Read the idea, work independently, then explain what changed.

TOPIC 01

2026 JM01

There is no real root of r²+r+1=0.

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Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

Find a₅+a₇ for the geometric sequence with the two given constraints.

2S3=a4−a1,a3+a5=72S_3=a_4-a_1,\quad a_3+a_5=7

Official paper · jm01-2026 · I.13 · PDF 3

Official original and suggested answers ↗ · Suggested answer PDF page 6

Skills and prerequisite lessons
  1. Option A55
  2. Option B77
  3. Option C2121
  4. Option D6363
  5. Option E3535

Working and explanation

BUILD THE REASONING

Hint 1
Write the first terms using first term a and ratio r.
Hint 2
Factor r³−1 instead of dividing prematurely by r−1.
Worked solution
  1. The nonzero sum ensures a is nonzero.

    2a(1+r+r2)=a(r3−1)  ⟹  (r−3)(r2+r+1)=02a(1+r+r^2)=a(r^3-1)\implies(r-3)(r^2+r+1)=0
  2. For real r, the quadratic factor is positive; shifting both terms by two multiplies the sum by r².

    r=3,a5+a7=r2(a3+a5)=9⋅7=63r=3,\quad a_5+a_7=r^2(a_3+a_5)=9\cdot7=63

D: 63.

Checks and common pitfalls: There is no real root of r²+r+1=0.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • The nonzero sum ensures a is nonzero.
    2a(1+r+r2)=a(r3−1)  ⟹  (r−3)(r2+r+1)=02a(1+r+r^2)=a(r^3-1)\implies(r-3)(r^2+r+1)=0
  • For real r, the quadratic factor is positive; shifting both terms by two multiplies the sum by r².
    r=3,a5+a7=r2(a3+a5)=9⋅7=63r=3,\quad a_5+a_7=r^2(a_3+a_5)=9\cdot7=63

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Curriculum and source notes ↗