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Count five-person committees from six boys and four girls, with at least three boys and one girl.

Read the idea, work independently, then explain what changed.

TOPIC 01

2026 JM01

A committee has no ordering; permutations would overcount.

Try it. Leave your reasoning visible.

Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

Count five-person committees from six boys and four girls, with at least three boys and one girl.

Official paper · jm01-2026 · I.10 · PDF 3

Official original and suggested answers ↗ · Suggested answer PDF page 6

Skills and prerequisite lessons
  1. Option A180180
  2. Option B200200
  3. Option C240240
  4. Option D252252
  5. Option E280280

Working and explanation

BUILD THE REASONING

Hint 1
List the possible numbers of boys and girls.
Hint 2
The cases are (3,2) and (4,1).
Worked solution
  1. Choose the members independently within each case.

    N3,2=(63)(42)=120,N4,1=(64)(41)=60N_{3,2}=\binom63\binom42=120,\quad N_{4,1}=\binom64\binom41=60
  2. The two cases are disjoint, so add.

    N=120+60=180N=120+60=180

A: 180 committees.

Checks and common pitfalls: A committee has no ordering; permutations would overcount.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • Choose the members independently within each case.
    N3,2=(63)(42)=120,N4,1=(64)(41)=60N_{3,2}=\binom63\binom42=120,\quad N_{4,1}=\binom64\binom41=60
  • The two cases are disjoint, so add.
    N=120+60=180N=120+60=180

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Curriculum and source notes ↗