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Intersect the quadratic-inequality set with the absolute-value set.

Read the idea, work independently, then explain what changed.

TOPIC 01

2026 JM01

The symbol ≥ includes both boundary points of B.

Try it. Leave your reasoning visible.

Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

Intersect the quadratic-inequality set with the absolute-value set.

A={x:x2+x−2≤0},B={x:∣x−1∣≥1}A=\{x:x^2+x-2\le0\},\quad B=\{x:|x-1|\ge1\}

Official paper · jm01-2026 · I.1 · PDF 2

Official original and suggested answers ↗ · Suggested answer PDF page 6

Skills and prerequisite lessons
  1. Option A[−2,0][-2,0]
  2. Option B[−2,1][-2,1]
  3. Option C[0,2][0,2]
  4. Option D[−2,2][-2,2]
  5. Option ER\mathbb R

Working and explanation

BUILD THE REASONING

Hint 1
Factor the quadratic and locate its two roots.
Hint 2
The absolute value describes two exterior intervals.
Worked solution
  1. The upward quadratic is nonpositive between its roots.

    (x+2)(x−1)≤0  ⟺  −2≤x≤1(x+2)(x-1)\le0\iff -2\le x\le1
  2. Keep only points in both sets.

    B=(−∞,0]∪[2,∞),A∩B=[−2,0]B=(-\infty,0]\cup[2,\infty),\quad A\cap B=[-2,0]

A: [−2,0].

Checks and common pitfalls: The symbol ≥ includes both boundary points of B.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • The upward quadratic is nonpositive between its roots.
    (x+2)(x−1)≤0  ⟺  −2≤x≤1(x+2)(x-1)\le0\iff -2\le x\le1
  • Keep only points in both sets.
    B=(−∞,0]∪[2,∞),A∩B=[−2,0]B=(-\infty,0]\cup[2,\infty),\quad A\cap B=[-2,0]

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Curriculum and source notes ↗