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With A=45° and cos C=4/5, calculate sin(2B).

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TOPIC 01

2025 JM01

The factor 2 in 1−2cos²C must be retained.

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Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

With A=45° and cos C=4/5, calculate sin(2B).

Official paper · jm01-2025 · II.3(b) · PDF 4

Official original and suggested answers ↗ · Suggested answer PDF page 6

Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Express B using the other two angles.
Hint 2
Use sin(2B)=−cos(2C).
Worked solution
  1. Double B=π−A−C.

    2B=3π2−2C,sin⁡2B=−cos⁡2C2B=\frac{3\pi}2-2C,\quad\sin2B=-\cos2C
  2. Substitute the known cosine into the double-angle identity.

    sin⁡2B=1−2cos⁡2C=1−2(45)2=−725\sin2B=1-2\cos^2C=1-2\left(\frac45\right)^2=-\frac7{25}

sin(2B)=−7/25.

Checks and common pitfalls: The factor 2 in 1−2cos²C must be retained.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • Double B=π−A−C.
    2B=3π2−2C,sin⁡2B=−cos⁡2C2B=\frac{3\pi}2-2C,\quad\sin2B=-\cos2C
  • Substitute the known cosine into the double-angle identity.
    sin⁡2B=1−2cos⁡2C=1−2(45)2=−725\sin2B=1-2\cos^2C=1-2\left(\frac45\right)^2=-\frac7{25}

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Curriculum and source notes ↗