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Six shifted numbers have median 8. Find their mean.

Read the idea, work independently, then explain what changed.

TOPIC 01

2025 JM01

The unsorted third and fourth entries do not define the median.

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Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

Six shifted numbers have median 8. Find their mean.

x+2,x+3,x+4,x−4,x−5,x−6x+2,x+3,x+4,x-4,x-5,x-6

Official paper · jm01-2025 · I.8 · PDF 2

Official original and suggested answers ↗ · Suggested answer PDF page 5

Skills and prerequisite lessons
  1. Option A33
  2. Option B77
  3. Option C88
  4. Option D99
  5. Option Exx

Working and explanation

BUILD THE REASONING

Hint 1
Sort the six expressions by their offsets.
Hint 2
The median is the average of the third and fourth sorted values.
Worked solution
  1. The middle two values are x−4 and x+2.

    (x−4)+(x+2)2=x−1=8  ⟹  x=9\frac{(x-4)+(x+2)}2=x-1=8\implies x=9
  2. The sum of all six offsets is −6.

    xˉ=6x−66=x−1=8\bar x=\frac{6x-6}6=x-1=8

C: 8.

Checks and common pitfalls: The unsorted third and fourth entries do not define the median.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • The middle two values are x−4 and x+2.
    (x−4)+(x+2)2=x−1=8  ⟹  x=9\frac{(x-4)+(x+2)}2=x-1=8\implies x=9
  • The sum of all six offsets is −6.
    xˉ=6x−66=x−1=8\bar x=\frac{6x-6}6=x-1=8

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Curriculum and source notes ↗