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Find the intersection with the finite set.

Read the idea, work independently, then explain what changed.

TOPIC 01

2025 JM01

The root −4 is included because the inequality is non-strict.

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Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

Find the intersection with the finite set.

A={x:x2+3x−4≥0},B={−4,−2,0,3}A=\{x:x^2+3x-4\ge0\},\quad B=\{-4,-2,0,3\}

Official paper · jm01-2025 · I.1 · PDF 2

Official original and suggested answers ↗ · Suggested answer PDF page 5

Skills and prerequisite lessons
  1. Option A{−4,3}\{-4,3\}
  2. Option B{−4,−2}\{-4,-2\}
  3. Option C{−2,3}\{-2,3\}
  4. Option D{0,3}\{0,3\}
  5. Option E{−2,0}\{-2,0\}

Working and explanation

BUILD THE REASONING

Hint 1
Factor the quadratic.
Hint 2
Test which listed elements lie outside its roots.
Worked solution
  1. The upward quadratic is nonnegative outside its roots.

    (x+4)(x−1)≥0  ⟺  x≤−4 or x≥1(x+4)(x-1)\ge0\iff x\le-4\ \text{or}\ x\ge1
  2. Filter the four listed elements.

    A∩B={−4,3}A\cap B=\{-4,3\}

A: {−4,3}.

Checks and common pitfalls: The root −4 is included because the inequality is non-strict.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • The upward quadratic is nonnegative outside its roots.
    (x+4)(x−1)≥0  ⟺  x≤−4 or x≥1(x+4)(x-1)\ge0\iff x\le-4\ \text{or}\ x\ge1
  • Filter the four listed elements.
    A∩B={−4,3}A\cap B=\{-4,3\}

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Curriculum and source notes ↗