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Evaluate the symmetric expression.

Read the idea, work independently, then explain what changed.

TOPIC 01

2024 JM01

The product x²·x⁻² is 1, so the cross term is 2.

Try it. Leave your reasoning visible.

Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

Evaluate the symmetric expression.

x2−3x+1=0,x4+x−4=?x^2-3x+1=0,\quad x^4+x^{-4}=?

Official paper · jm01-2024 · I.14 · PDF 3

Official original and suggested answers ↗ · Suggested answer PDF page 5

Skills and prerequisite lessons
  1. Option A22
  2. Option B4747
  3. Option C4949
  4. Option D7979
  5. Option E8181

Working and explanation

BUILD THE REASONING

Hint 1
Divide by x; x is nonzero.
Hint 2
Square twice and subtract the cross term each time.
Worked solution
  1. Find x²+x⁻².

    x+x−1=3  ⟹  x2+x−2=9−2=7x+x^{-1}=3\implies x^2+x^{-2}=9-2=7
  2. Square again.

    x4+x−4=72−2=47x^4+x^{-4}=7^2-2=47

B: 47.

Checks and common pitfalls: The product x²·x⁻² is 1, so the cross term is 2.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • Find x²+x⁻².
    x+x−1=3  ⟹  x2+x−2=9−2=7x+x^{-1}=3\implies x^2+x^{-2}=9-2=7
  • Square again.
    x4+x−4=72−2=47x^4+x^{-4}=7^2-2=47

Think first. Reveal a hint when the class is ready.

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Curriculum and source notes ↗