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Find a from the stated intersection.

Read the idea, work independently, then explain what changed.

TOPIC 01

2024 JM01

Dividing by positive 3 does not reverse the inequality.

Try it. Leave your reasoning visible.

Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

Find a from the stated intersection.

A={x:x2−3x−4≤0}, B={x:3x+a≥0}, A∩B=[2,4]A=\{x:x^2-3x-4\le0\},\ B=\{x:3x+a\ge0\},\ A\cap B=[2,4]

Official paper · jm01-2024 · I.1 · PDF 2

Official original and suggested answers ↗ · Suggested answer PDF page 5

Skills and prerequisite lessons
  1. Option A−12-12
  2. Option B−6-6
  3. Option C−3-3
  4. Option D66
  5. Option E1212

Working and explanation

BUILD THE REASONING

Hint 1
Factor the quadratic.
Hint 2
Match the left endpoint of B with 2.
Worked solution
  1. The quadratic is nonpositive between its roots.

    A=[−1,4],B=[−a/3,∞)A=[-1,4],\quad B=[-a/3,\infty)
  2. The intersection begins at 2, so −a/3=2.

    a=−6a=-6

B: a=−6.

Checks and common pitfalls: Dividing by positive 3 does not reverse the inequality.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • The quadratic is nonpositive between its roots.
    A=[−1,4],B=[−a/3,∞)A=[-1,4],\quad B=[-a/3,\infty)
  • The intersection begins at 2, so −a/3=2.
    a=−6a=-6

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Curriculum and source notes ↗