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Sₙ=3ⁿ⁺¹−2k is the partial sum of a geometric sequence. Find k and aₙ.

Read the idea, work independently, then explain what changed.

TOPIC 01

2023 JM01

The difference formula for n≥2 cannot determine a₁ without checking S₁.

Try it. Leave your reasoning visible.

Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

Sₙ=3ⁿ⁺¹−2k is the partial sum of a geometric sequence. Find k and aₙ.

Official paper · jm01-2023 · II.3(a) · PDF 4

Official original and suggested answers ↗ · Suggested answer PDF page 6

Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Compute a₁ separately, then a₂ and a₃ by differences.
Hint 2
Use a₂²=a₁a₃.
Worked solution
  1. The first three terms are 9−2k,18,54.

    182=54(9−2k)  ⟹  k=3/218^2=54(9-2k)\implies k=3/2
  2. Identify first term 6 and ratio 3.

    an=6⋅3n−1=2⋅3na_n=6\cdot3^{n-1}=2\cdot3^n

k=3/2; aₙ=2·3ⁿ.

Checks and common pitfalls: The difference formula for n≥2 cannot determine a₁ without checking S₁.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • The first three terms are 9−2k,18,54.
    182=54(9−2k)  ⟹  k=3/218^2=54(9-2k)\implies k=3/2
  • Identify first term 6 and ratio 3.
    an=6⋅3n−1=2⋅3na_n=6\cdot3^{n-1}=2\cdot3^n

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Curriculum and source notes ↗