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A,B lie in quadrant II, with sin A=2/5 and sin B=4/5. Find sin(A+B).

Read the idea, work independently, then explain what changed.

TOPIC 01

2023 JM01

Positive sine does not imply positive cosine in quadrant II.

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Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

A,B lie in quadrant II, with sin A=2/5 and sin B=4/5. Find sin(A+B).

Official paper · jm01-2023 · I.13 · PDF 3

Official original and suggested answers ↗ · Suggested answer PDF page 5

Skills and prerequisite lessons
  1. Option A−6−42125\frac{-6-4\sqrt{21}}{25}
  2. Option B13/2513/25
  3. Option C18/2518/25
  4. Option D−12−22125\frac{-12-2\sqrt{21}}{25}
  5. Option E12+22125\frac{12+2\sqrt{21}}{25}

Working and explanation

BUILD THE REASONING

Hint 1
Both cosines are negative.
Hint 2
Use the sine addition formula.
Worked solution
  1. Determine the cosines with the quadrant signs.

    cos⁡A=−21/5,cos⁡B=−3/5\cos A=-\sqrt{21}/5,\quad\cos B=-3/5
  2. Substitute into the addition formula.

    sin⁡(A+B)=25(−35)+(−215)45=−6−42125\sin(A+B)=\frac25\left(-\frac35\right)+\left(-\frac{\sqrt{21}}5\right)\frac45=\frac{-6-4\sqrt{21}}{25}

A.

Checks and common pitfalls: Positive sine does not imply positive cosine in quadrant II.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • Determine the cosines with the quadrant signs.
    cos⁡A=−21/5,cos⁡B=−3/5\cos A=-\sqrt{21}/5,\quad\cos B=-3/5
  • Substitute into the addition formula.
    sin⁡(A+B)=25(−35)+(−215)45=−6−42125\sin(A+B)=\frac25\left(-\frac35\right)+\left(-\frac{\sqrt{21}}5\right)\frac45=\frac{-6-4\sqrt{21}}{25}

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Curriculum and source notes ↗