← Senior Mathematics Studio

LEARN · EXPLAIN · REVISE

An arithmetic sequence has a₇=80 and a₁₆=26. Find a₃₄.

Read the idea, work independently, then explain what changed.

TOPIC 01

2023 JM01

Use index differences, not the indices themselves.

Try it. Leave your reasoning visible.

Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

An arithmetic sequence has a₇=80 and a₁₆=26. Find a₃₄.

Official paper · jm01-2023 · I.10 · PDF 3

Official original and suggested answers ↗ · Suggested answer PDF page 5

Skills and prerequisite lessons
  1. Option A−6-6
  2. Option B−82-82
  3. Option C−88-88
  4. Option D−198-198
  5. Option E−204-204

Working and explanation

BUILD THE REASONING

Hint 1
There are nine common differences between the given terms.
Hint 2
Advance eighteen terms from a₁₆.
Worked solution
  1. Find d.

    d=(26−80)/(16−7)=−6d=(26-80)/(16-7)=-6
  2. Evaluate the required term.

    a34=26+18(−6)=−82a_{34}=26+18(-6)=-82

B: −82.

Checks and common pitfalls: Use index differences, not the indices themselves.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • Find d.
    d=(26−80)/(16−7)=−6d=(26-80)/(16-7)=-6
  • Evaluate the required term.
    a34=26+18(−6)=−82a_{34}=26+18(-6)=-82

Think first. Reveal a hint when the class is ready.

Focus on one question

No sign-in. Work stays in this browser. Export before clearing browser data. Written reasoning is assessed with a checklist.

Curriculum and source notes ↗