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Solve in radians on 0≤θ≤2π.

Read the idea, work independently, then explain what changed.

TOPIC 01

2022 JM01

Both cosine solutions must be retained.

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Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

Solve in radians on 0≤θ≤2π.

3cos⁡θ−sin⁡θ=−1\sqrt3\cos\theta-\sin\theta=-1

Official paper · jm01-2022 · II.4(b) · PDF 4

Official original and suggested answers ↗ · Suggested answer PDF page 7

Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Use part (a) to obtain cos(θ+π/6)=−1/2.
Hint 2
Shift the argument interval before selecting the angles.
Worked solution
  1. The shifted angle is in [π/6,13π/6].

    θ+π/6=2π/3 or 4π/3\theta+\pi/6=2\pi/3\text{ or }4\pi/3
  2. Subtract the phase.

    θ=π/2 or 7π/6\theta=\pi/2\text{ or }7\pi/6

θ=π/2 or 7π/6.

Checks and common pitfalls: Both cosine solutions must be retained.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • The shifted angle is in [π/6,13π/6].
    θ+π/6=2π/3 or 4π/3\theta+\pi/6=2\pi/3\text{ or }4\pi/3
  • Subtract the phase.
    θ=π/2 or 7π/6\theta=\pi/2\text{ or }7\pi/6

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Curriculum and source notes ↗