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Find the maximum and minimum of g(x)=f(3sin x).

Read the idea, work independently, then explain what changed.

TOPIC 01

2022 JM01

Optimise f over the inner range, not over all real t.

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Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

Find the maximum and minimum of g(x)=f(3sin x).

f(t)=(t−2)2−9f(t)=(t-2)^2-9

Official paper · jm01-2022 · II.1(c) · PDF 4

Official original and suggested answers ↗ · Suggested answer PDF page 6

Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
The inner value t=3sin x ranges over [−3,3].
Hint 2
Compare the vertex and both endpoints.
Worked solution
  1. The vertex t=2 belongs to the inner range.

    gmin⁡=f(2)=−9g_{\min}=f(2)=-9
  2. The farthest endpoint from 2 is −3.

    gmax⁡=f(−3)=25−9=16g_{\max}=f(-3)=25-9=16

Maximum 16; minimum −9.

Checks and common pitfalls: Optimise f over the inner range, not over all real t.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • The vertex t=2 belongs to the inner range.
    gmin⁡=f(2)=−9g_{\min}=f(2)=-9
  • The farthest endpoint from 2 is −3.
    gmax⁡=f(−3)=25−9=16g_{\max}=f(-3)=25-9=16

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Curriculum and source notes ↗