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Find 1/a+1/b.

Read the idea, work independently, then explain what changed.

TOPIC 01

2022 JM01

The common value is √10, so its logarithm is half ln10.

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Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

Find 1/a+1/b.

2a=5b=102^a=5^b=\sqrt{10}

Official paper · jm01-2022 · I.6 · PDF 2

Official original and suggested answers ↗ · Suggested answer PDF page 5

Skills and prerequisite lessons
  1. Option A22
  2. Option B11
  3. Option C2\sqrt2
  4. Option D2/2\sqrt2/2
  5. Option E1/21/2

Working and explanation

BUILD THE REASONING

Hint 1
Take logarithms in each equality.
Hint 2
The reciprocal exponents share the same denominator.
Worked solution
  1. Express the reciprocals.

    1a=ln⁡2ln⁡10,1b=ln⁡5ln⁡10\frac1a=\frac{\ln2}{\ln\sqrt{10}},\quad\frac1b=\frac{\ln5}{\ln\sqrt{10}}
  2. Combine using ln2+ln5=ln10.

    1a+1b=ln⁡10(1/2)ln⁡10=2\frac1a+\frac1b=\frac{\ln10}{(1/2)\ln10}=2

A: 2.

Checks and common pitfalls: The common value is √10, so its logarithm is half ln10.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • Express the reciprocals.
    1a=ln⁡2ln⁡10,1b=ln⁡5ln⁡10\frac1a=\frac{\ln2}{\ln\sqrt{10}},\quad\frac1b=\frac{\ln5}{\ln\sqrt{10}}
  • Combine using ln2+ln5=ln10.
    1a+1b=ln⁡10(1/2)ln⁡10=2\frac1a+\frac1b=\frac{\ln10}{(1/2)\ln10}=2

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Curriculum and source notes ↗