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Find all p for which the equation has a real solution.

Read the idea, work independently, then explain what changed.

TOPIC 01

2022 JM01

The question says equation, so the linear case must not be discarded.

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Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

Find all p for which the equation has a real solution.

px2−2(p+3)x+p−1=0px^2-2(p+3)x+p-1=0

Official paper · jm01-2022 · I.5 · PDF 2

Official original and suggested answers ↗ · Suggested answer PDF page 5

Skills and prerequisite lessons
  1. Option A0≤p≤5/70\le p\le5/7
  2. Option Bp≥−5/7p\ge-5/7
  3. Option C−5/7≤p≤1-5/7\le p\le1
  4. Option Dp≥−9/7p\ge-9/7
  5. None of these

Working and explanation

BUILD THE REASONING

Hint 1
Treat p=0 separately.
Hint 2
For p≠0 require a nonnegative discriminant.
Worked solution
  1. The quadratic discriminant simplifies to a linear expression.

    Δ=4(p+3)2−4p(p−1)=4(7p+9)≥0  ⟺  p≥−9/7\Delta=4(p+3)^2-4p(p-1)=4(7p+9)\ge0\iff p\ge-9/7
  2. At p=0, the linear equation −6x−1=0 also has a real solution, already inside this range.

D: p≥−9/7.

Checks and common pitfalls: The question says equation, so the linear case must not be discarded.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • The quadratic discriminant simplifies to a linear expression.
    Δ=4(p+3)2−4p(p−1)=4(7p+9)≥0  ⟺  p≥−9/7\Delta=4(p+3)^2-4p(p-1)=4(7p+9)\ge0\iff p\ge-9/7
  • At p=0, the linear equation −6x−1=0 also has a real solution, already inside this range.

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Curriculum and source notes ↗