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Derive the completed-square identity from the stated relation.

Read the idea, work independently, then explain what changed.

TOPIC 01

2021 JM01

The square is x−my, not y−mx in this particular rearrangement.

Try it. Leave your reasoning visible.

Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

Derive the completed-square identity from the stated relation.

x,y>0,0<m<1,y2−2mxy+x2=a2x,y>0,\quad0<m<1,\quad y^2-2mxy+x^2=a^2

Official paper · jm01-2021 · II.3(a) · PDF 4

Official original and suggested answers ↗ · Suggested answer PDF page 7

Skills and prerequisite lessons

Working and explanation

BUILD THE REASONING

Hint 1
Complete the square in x, keeping y as a parameter.
Hint 2
The cross term must remain −2mxy.
Worked solution
  1. Split the y² coefficient after completing the x square.

    x2−2mxy+y2=(x−my)2+(1−m2)y2x^2-2mxy+y^2=(x-my)^2+(1-m^2)y^2
  2. Use the original equality and rearrange.

    (1−m2)y2=a2−(x−my)2(1-m^2)y^2=a^2-(x-my)^2

(1−m²)y²=a²−(x−my)².

Checks and common pitfalls: The square is x−my, not y−mx in this particular rearrangement.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • Split the y² coefficient after completing the x square.
    x2−2mxy+y2=(x−my)2+(1−m2)y2x^2-2mxy+y^2=(x-my)^2+(1-m^2)y^2
  • Use the original equality and rearrange.
    (1−m2)y2=a2−(x−my)2(1-m^2)y^2=a^2-(x-my)^2

Think first. Reveal a hint when the class is ready.

Focus on one question

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Curriculum and source notes ↗