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The equation has a real solution. Choose the official best answer describing the attainable range of k.

Read the idea, work independently, then explain what changed.

TOPIC 01

2021 JM01

Do not include k=0: it is a limiting value, not an attained one.

Try it. Leave your reasoning visible.

Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

The equation has a real solution. Choose the official best answer describing the attainable range of k.

9−x2−4⋅3−x2=k9^{-x^2}-4\cdot3^{-x^2}=k

Official paper · jm01-2021 · I.7 · PDF 2

Official original and suggested answers ↗ · Suggested answer PDF page 5

Skills and prerequisite lessons
  1. Option Ak>0k>0
  2. Option B−4≤k≤1-4\le k\le1
  3. Option C−3≤k<0-3\le k<0
  4. Option D0<k≤30<k\le3
  5. None of these

Working and explanation

BUILD THE REASONING

Hint 1
Set u=3^(−x²) and find its exact range.
Hint 2
On 0<u≤1, the expression u²−4u decreases.
Worked solution
  1. The exponent is nonpositive, and a positive exponential never reaches zero.

    u=3−x2∈(0,1]u=3^{-x^2}\in(0,1]
  2. Compare endpoints and the unattained limiting value.

    k=u2−4u=(u−2)2−4∈[−3,0)k=u^2-4u=(u-2)^2-4\in[-3,0)
  3. Every u in (0,1] is attainable by a real x.

    x=±−log⁡3ux=\pm\sqrt{-\log_3u}

C: −3≤k<0 is the exact range.

Checks and common pitfalls: Do not include k=0: it is a limiting value, not an attained one.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • The exponent is nonpositive, and a positive exponential never reaches zero.
    u=3−x2∈(0,1]u=3^{-x^2}\in(0,1]
  • Compare endpoints and the unattained limiting value.
    k=u2−4u=(u−2)2−4∈[−3,0)k=u^2-4u=(u-2)^2-4\in[-3,0)
  • Every u in (0,1] is attainable by a real x.
    x=±−log⁡3ux=\pm\sqrt{-\log_3u}

Think first. Reveal a hint when the class is ready.

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Curriculum and source notes ↗