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Two equal disks inside a 7 cm by 4 cm rectangle touch its top and bottom sides. Their overlap has area 3 cm². Find the shaded area outside both disks.

Read the idea, work independently, then explain what changed.

TOPIC 01

2021 JM01

The disks overlap; no external tangency between the disks is assumed.

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Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

Two equal disks inside a 7 cm by 4 cm rectangle touch its top and bottom sides. Their overlap has area 3 cm². Find the shaded area outside both disks.

Overlapping disks in a 7 cm by 4 cm rectangle / 長方形內兩個相交圓7 cm4 cm3 cm²

Official paper · jm01-2021 · I.6 · PDF 2

Official original and suggested answers ↗ · Suggested answer PDF page 5

Skills and prerequisite lessons
  1. Option A31−8π31-8\pi
  2. Option B27−8π27-8\pi
  3. Option C27−4π27-4\pi
  4. Option D21−4π21-4\pi
  5. None of these

Working and explanation

BUILD THE REASONING

Hint 1
The rectangle height is a circle diameter.
Hint 2
Subtract the union of the two disks, counting the overlap once.
Worked solution
  1. Each radius is 2 cm, so each disk area is 4π.

    r=4/2=2,∣D1∣=∣D2∣=4πr=4/2=2,\quad|D_1|=|D_2|=4\pi
  2. Use inclusion–exclusion before subtracting from the rectangle.

    ∣D1∪D2∣=8π−3;S=28−(8π−3)=31−8π|D_1\cup D_2|=8\pi-3;\quad S=28-(8\pi-3)=31-8\pi

A: 31−8π cm².

Checks and common pitfalls: The disks overlap; no external tangency between the disks is assumed.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • Each radius is 2 cm, so each disk area is 4π.
    r=4/2=2,∣D1∣=∣D2∣=4πr=4/2=2,\quad|D_1|=|D_2|=4\pi
  • Use inclusion–exclusion before subtracting from the rectangle.
    ∣D1∪D2∣=8π−3;S=28−(8π−3)=31−8π|D_1\cup D_2|=8\pi-3;\quad S=28-(8\pi-3)=31-8\pi

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Curriculum and source notes ↗