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Simplify the radical expression exactly.

Read the idea, work independently, then explain what changed.

TOPIC 01

2021 JM01

Keep the cross term −2√(35·33) when squaring.

Try it. Leave your reasoning visible.

Use one hint at a time. A correction explains what changed, not just the final answer.

01 / Standard#Your turn

Simplify the radical expression exactly.

140−13235+33\frac{\sqrt{140}-\sqrt{132}}{\sqrt{35}+\sqrt{33}}

Official paper · jm01-2021 · I.14 · PDF 3

Official original and suggested answers ↗ · Suggested answer PDF page 5

Skills and prerequisite lessons
  1. Option A68−2115568-2\sqrt{1155}
  2. Option B68−115568-\sqrt{1155}
  3. Option C(34−1155)/2(34-\sqrt{1155})/2
  4. Option D34−115534-\sqrt{1155}
  5. Option E68+2115568+2\sqrt{1155}

Working and explanation

BUILD THE REASONING

Hint 1
Factor 4 from each radicand in the numerator.
Hint 2
Rationalize with √35−√33.
Worked solution
  1. Simplify the numerator before rationalizing.

    2(35−33)35+33\frac{2(\sqrt{35}-\sqrt{33})}{\sqrt{35}+\sqrt{33}}
  2. The conjugate denominator is 35−33=2.

    2(35−33)235−33=68−21155\frac{2(\sqrt{35}-\sqrt{33})^2}{35-33}=68-2\sqrt{1155}

A: 68−2√1155.

Checks and common pitfalls: Keep the cross term −2√(35·33) when squaring.

Reasoning checklist · self / teacher assessment
  • Teaching assessment checklist, independently authored. Use the original paper for official marks.
  • Simplify the numerator before rationalizing.
    2(35−33)35+33\frac{2(\sqrt{35}-\sqrt{33})}{\sqrt{35}+\sqrt{33}}
  • The conjugate denominator is 35−33=2.
    2(35−33)235−33=68−21155\frac{2(\sqrt{35}-\sqrt{33})^2}{35-33}=68-2\sqrt{1155}

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Curriculum and source notes ↗