Undoing a rule
An inverse exchanges the original domain and range and requires a one-to-one rule.
LEARN · EXPLAIN · REVISE
Read the idea, work independently, then explain what changed.
2027 JM02 考試大綱 · 1. Functions · PDF 2 / printed page 2
Revisit first: Function concept and representationsBasic properties of functions
TOPIC 01
Build understanding of inverse functions and domain restrictions through definitions, contrasting cases and justified applications.
An inverse exchanges the original domain and range and requires a one-to-one rule.
Restricting a quadratic to either side of its vertex creates an invertible rule.
PREDICT → EXPLORE → EXPLAIN → TRANSFER
Lesson question: Before calculating, predict how the conclusion changes when one defining condition in inverse functions and domain restrictions changes. Record a reason.
Model exploration: predict which displayed result changes with the parameters, check the values, and compare the observation with the lesson question.
Restrict y=(x−0)²+0 to x≥0. Its inverse is y=0+√(x−0), x≥0. The graphs reflect in y=x; their domain and range exchange.
Explain: Compare two admissible cases and one boundary or invalid case. Explain the observed difference using the stated definition.
Transfer: Construct a new example and a tempting incorrect solution. Repair the solution by naming the missing condition.
Use one hint at a time. A correction explains what changed, not just the final answer.
Working and explanation
BUILD THE REASONING
Specify a one-to-one domain, solve for the input, then exchange the variables.
Calculate or simplify this relation.
An inverse function is not the reciprocal 1/f(x).
f⁻¹(x)=(x−3)/2.
Checks and common pitfalls: An inverse function is not the reciprocal 1/f(x).
Think first. Reveal a hint when the class is ready.
Working and explanation
BUILD THE REASONING
Specify a one-to-one domain, solve for the input, then exchange the variables.
Calculate or simplify this relation.
The original range becomes the inverse domain.
f⁻¹(x)=2+1/x, x≠0.
Checks and common pitfalls: The original range becomes the inverse domain.
Think first. Reveal a hint when the class is ready.
Working and explanation
BUILD THE REASONING
Specify a one-to-one domain, solve for the input, then exchange the variables.
Calculate or simplify this relation.
The output 1 would require 2=−1, which is false.
f⁻¹(x)=(x+2)/(x−1), x≠1.
Checks and common pitfalls: The output 1 would require 2=−1, which is false.
Think first. Reveal a hint when the class is ready.
Working and explanation
BUILD THE REASONING
Specify a one-to-one domain, solve for the input, then exchange the variables.
Calculate or simplify this relation.
An inverse function is not the reciprocal 1/f(x).
f⁻¹(x)=(x−3)/3.
Checks and common pitfalls: An inverse function is not the reciprocal 1/f(x).
Think first. Reveal a hint when the class is ready.
Working and explanation
BUILD THE REASONING
Specify a one-to-one domain, solve for the input, then exchange the variables.
Calculate or simplify this relation.
The original range becomes the inverse domain.
f⁻¹(x)=3+1/x, x≠0.
Checks and common pitfalls: The original range becomes the inverse domain.
Think first. Reveal a hint when the class is ready.
Working and explanation
BUILD THE REASONING
Specify a one-to-one domain, solve for the input, then exchange the variables.
Calculate or simplify this relation.
The unrestricted quadratic does not have an inverse function on the whole real line.
f⁻¹(x)=3+√x, x≥0.
Checks and common pitfalls: The unrestricted quadratic does not have an inverse function on the whole real line.
Think first. Reveal a hint when the class is ready.
Working and explanation
BUILD THE REASONING
Specify a one-to-one domain, solve for the input, then exchange the variables.
Calculate or simplify this relation.
Composition order matters outside the relevant domain and range.
The requested value is 5.
Checks and common pitfalls: Composition order matters outside the relevant domain and range.
Think first. Reveal a hint when the class is ready.
Working and explanation
BUILD THE REASONING
Specify a one-to-one domain, solve for the input, then exchange the variables.
Calculate or simplify this relation.
Surjectivity onto the stated range alone does not give injectivity.
No: f(1)=f(−1)=1.
Checks and common pitfalls: Surjectivity onto the stated range alone does not give injectivity.
Think first. Reveal a hint when the class is ready.
Working and explanation
BUILD THE REASONING
Specify a one-to-one domain, solve for the input, then exchange the variables.
Calculate or simplify this relation.
Writing ± without a domain does not define an inverse function.
x≤3: f⁻¹(y)=3−√y; x≥3: f⁻¹(y)=3+√y, y≥0.
Checks and common pitfalls: Writing ± without a domain does not define an inverse function.
Think first. Reveal a hint when the class is ready.
Working and explanation
BUILD THE REASONING
Specify a one-to-one domain, solve for the input, then exchange the variables.
Calculate or simplify this relation.
The output 1 would require 3=−1, which is false.
f⁻¹(x)=(x+3)/(x−1), x≠1.
Checks and common pitfalls: The output 1 would require 3=−1, which is false.
Think first. Reveal a hint when the class is ready.
Working and explanation
BUILD THE REASONING
Specify a one-to-one domain, solve for the input, then exchange the variables.
Calculate or simplify this relation.
An inverse function is not the reciprocal 1/f(x).
f⁻¹(x)=(x−3)/4.
Checks and common pitfalls: An inverse function is not the reciprocal 1/f(x).
Think first. Reveal a hint when the class is ready.
Working and explanation
BUILD THE REASONING
Specify a one-to-one domain, solve for the input, then exchange the variables.
Calculate or simplify this relation.
The original range becomes the inverse domain.
f⁻¹(x)=4+1/x, x≠0.
Checks and common pitfalls: The original range becomes the inverse domain.
Think first. Reveal a hint when the class is ready.
Working and explanation
BUILD THE REASONING
Specify a one-to-one domain, solve for the input, then exchange the variables.
Calculate or simplify this relation.
The unrestricted quadratic does not have an inverse function on the whole real line.
f⁻¹(x)=4+√x, x≥0.
Checks and common pitfalls: The unrestricted quadratic does not have an inverse function on the whole real line.
Think first. Reveal a hint when the class is ready.
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