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Prove A,B,C are collinear and locate C relative to AB.

Read the idea, work independently, then explain what changed.

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高一必修 第二册(A版).pdf · 6.3 · PDF 32 / printed page 25

Revisit first: Vectors as displacements

TOPIC 01

Coordinates, bases and division

Convert arrows to coordinates, recover unknown endpoints and test when a basis actually determines coordinates.

What you will be able to explain

  • Subtract endpoints in the correct order.
  • Use affine weights for a midpoint, division point and centroid.
  • Distinguish an independent basis from parallel generating vectors.

Try it. Leave your reasoning visible.

Use one hint at a time. A correction explains what changed, not just the final answer.

Examples 1–3: study a full demonstration; finish a solution from its first step; then choose a method independently before opening the solution. The remaining exercises may continue after class.

01 / Transfer#Worked example

Prove A,B,C are collinear and locate C relative to AB.

A=(0,0),B=(2,3),C=(4,6)A=(0,0),B=(2,3),C=(4,6)
Skills and prerequisite lessons

Scope: JM02

Working and explanation

BUILD THE REASONING

Hint 1
Compare AC with AB.
Hint 2
A factor greater than one places C beyond B.
Worked solution
  1. The displacements are proportional.

    AC=(4,6)=2ABAC=(4,6)=2AB
  2. Since 2>1, C lies on the ray AB beyond B.

Collinear; B is the midpoint of AC.

Checks and common pitfalls: Parallel displacement vectors through A imply collinearity; equal lengths alone do not.

Reasoning checklist · self / teacher assessment
  • Collinear; B is the midpoint of AC.
  • Parallel displacement vectors through A imply collinearity; equal lengths alone do not.

Think first. Reveal a hint when the class is ready.

Focus on one question

Teacher preparation and assessment

40-minute lesson

MinutesFocusTeaching and student action
5Prediction and diagnosisDiagnose reversed endpoint subtraction.
8Concept derivationDerive division and centroid expressions using displacements.
10Guided applicationSolve one independent and one dependent basis system.
12Transfer and explanationRecover a triangle from its centroid and verify it is nondegenerate.
5Exit evidenceCheck a proposed basis counterexample.

Question sequence

  • Which subtraction gives an arrow pointing from A to B?
  • Why do the coefficients of a point division sum to one?

Board development

  • Mark A, P, B on a number line before substituting into the division formula.
  • Put the independent and dependent basis systems side by side and compare determinants.

Expected correct and incorrect responses

  • Students reverse the ratio weights. Check whether the longer AP places P nearer B.
  • Correct: “P is two thirds of the way from A to B, so P=(6,4).”
  • Incorrect: “AP:PB=2:1 means P=(A+2B)/2.”

Follow-up questions

  • Translate every vertex by the same vector. How does the centroid move?

Remediation

  • Use A=0 and B=9 to locate a 2:1 internal division before doing two coordinates.

Exit check

  • Give a dependent pair and a vector that it cannot represent.

Assessment checklist and sample responses

  • Require the endpoint order, correct affine weights and a uniqueness check where a basis is used. Sample: G=(A+B+C)/3 implies C=3G−A−B.
    Correct: “P is two thirds of the way from A to B, so P=(6,4).”

No sign-in. Work stays in this browser. Export before clearing browser data. Written reasoning is assessed with a checklist.

Curriculum and source notes ↗