LEARN · EXPLAIN · REVISE

Solve the strict inequality.

Read the idea, work independently, then explain what changed.

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高一必修第一册(A版).pdf · 2.3 · PDF 57 / printed page 50

Revisit first: Roots and completeness of solutions

TOPIC 01

Quadratic signs and solution sets

Use roots to partition a line, then retain endpoint and domain conditions.

What you will be able to explain

Justify the sign on each interval instead of memorising an unqualified inside/outside rule.
Intersect an algebraic solution set with modelling and domain restrictions.

Try it. Leave your reasoning visible.

Use one hint at a time. A correction explains what changed, not just the final answer.

Examples 1–3: study a full demonstration; finish a solution from its first step; then choose a method independently before opening the solution. The remaining exercises may continue after class.

01 / Foundation#Worked example

Solve the strict inequality.

(x-1)(x-4)>0

All inputs are real unless a smaller domain is stated.

Skills and prerequisite lessons

Scope: JM01 / JM02

Working and explanation

BUILD THE REASONING

Hint 1

Partition at the two roots.

Hint 2

A product is positive when both factors have the same sign.

Worked solution

Locate the boundaries and signs.
$1,4;\quad+,-,+$
Exclude roots because the inequality is strict.
$x<1\text{ or }x>4$

(−∞,1)∪(4,∞).

Checks and common pitfalls: The endpoints make the product zero, not positive.

Think first. Reveal a hint when the class is ready.

Teacher preparation and assessment

40-minute lesson

Minutes	Focus	Teaching and student action
5	Diagnose regions	Use the negative-leading and repeated-root diagnostics.
8	Build signs	Students multiply factor signs on three intervals.
10	Endpoints and domains	Pairs contrast strict, weak, radical and rational restrictions.
12	Model and quantify	Groups solve rectangle feasibility and then the all-real parameter condition.
5	Exit interval	Require a sign reason and correct endpoint notation.

Question sequence

What information is missing if we only solve the equation?
Does “for every x” permit checking only three values?

Board development

Multiply signs before drawing the solution.
$a(x-r_1)(x-r_2)$
Intersect with original restrictions.
$S_{\mathrm{valid}}=S_{\mathrm{sign}}\cap D$

Expected correct and incorrect responses

“The square is nonnegative, so strict negativity is impossible” is a complete reason.
“Include −2 because ≥ allows equality” overlooks the denominator.

Follow-up questions

Which endpoint would survive after adding a denominator?

Remediation

For inside/outside errors, rebuild a two-factor sign chart instead of recalling a slogan.

Exit check

Solve (x−1)²≥0 and (x−1)²>0; explain the single-point difference.

Assessment checklist and sample responses

2 marks: sign regions and equality.
Full: (2,3] after intersection; incomplete: [2,3].
2 marks: model interpretation.
Full: arbitrary side [3,7], shorter side [3,5]; partial: no shorter-side restriction.