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Find the intersections, retaining the vertex.

Read the idea, work independently, then explain what changed.

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高二選擇性必修 第一册(A版).pdf · 3.1 · PDF 110 / printed page 105

Revisit first: Ellipse: definition, axes and constraintsHyperbola: branches and asymptotesParabola: focus and directrix

TOPIC 01

Conic intersections, chords and inverse problems

Solve line–conic systems with degree and domain checks; use Vieta for midpoint loci and reconstruct a chord from its midpoint.

What you will be able to explain

  • Retain all roots and substitute them into the original system.
  • Use the discriminant only for an actual quadratic.
  • Use root sums and products without unnecessarily solving every endpoint.

Try it. Leave your reasoning visible.

Use one hint at a time. A correction explains what changed, not just the final answer.

Examples 1–3: study a full demonstration; finish a solution from its first step; then choose a method independently before opening the solution. The remaining exercises may continue after class.

01 / Standard#Worked example

Find the intersections, retaining the vertex.

y2=4x, y=xy^2=4x,\ y=x
Skills and prerequisite lessons

Scope: JM01 / JM02

Working and explanation

BUILD THE REASONING

Hint 1
Substitute y=x.
Hint 2
Factor without dividing by x.
Worked solution
  1. The equation includes a zero root.

    x2−4x=x(x−4)=0x^2-4x=x(x-4)=0
  2. Return each root to y=x.

    (x,y)=(0,0),(4,4)(x,y)=(0,0),(4,4)

(0,0) and (4,4).

Checks and common pitfalls: Dividing by x would lose the vertex.

Reasoning checklist · self / teacher assessment
  • (0,0) and (4,4).
  • Dividing by x would lose the vertex.

Think first. Reveal a hint when the class is ready.

Focus on one question

Teacher preparation and assessment

40-minute lesson

MinutesFocusTeaching and student action
5Prediction and diagnosisFind the lost zero root in a proposed solution.
8Concept derivationDerive the ellipse-line quadratic and Vieta midpoint.
10Guided applicationClassify secant, tangent, external and degree-loss cases.
12Transfer and explanationReconstruct a chord and prove the full midpoint locus including the vertical case.
5Exit evidenceWrite the degree condition beside the discriminant rule.

Question sequence

  • What is the actual degree after substitution?
  • Can the midpoint be found without writing both radicals?

Board development

  • Place degree check before discriminant, then back-substitution after roots.
  • For the midpoint locus, reserve a box for the vertical chord and the reverse parametrization.

Expected correct and incorrect responses

  • Students prove only that chord midpoints satisfy an ellipse equation. Ask how an arbitrary point on that ellipse recovers a chord.
  • Correct: “I keep x=0 when factoring x(x−4)=0, and then use y=x.”
  • Incorrect: “Dividing by x gives x=4, so (4,4) is the only intersection.”

Follow-up questions

  • Which datum determines the slope in the inverse-parabola chord problem?

Remediation

  • Factor x(x−4)=0 before any division; check each point in y=x.

Exit check

  • State the extra check needed before using Δ=0 as a tangency test.

Assessment checklist and sample responses

  • Credit degree, full root retention, back-substitution and a two-way locus argument. Sample: finite m covers k>0; the vertical chord supplies (0,0), completing the midpoint locus.
    Correct: “I keep x=0 when factoring x(x−4)=0, and then use y=x.”

No sign-in. Work stays in this browser. Export before clearing browser data. Written reasoning is assessed with a checklist.

Curriculum and source notes ↗